Answer:
Explanation:
The relative massive alpha particles could go through the gold foil without being deviated of their trajectory or only small deviations due to the uniformity distribution positive charge of the protons.
Answer:
3
Explanation:
For an ideal ramp, M.A/V.R = 1 where M.A = mechanical advantage and V.R = velocity ratio.
Now, V.R = distance moved by effort, d'/distance moved by load, d = d'/d
Now, d' = 3 m and d = 1 m.
So, V.R = d'/d = 3 m/1 m = 3
From M.A/V.R = 1
M.A = V.R = 3
So, the ideal mechanical advantage of the ramp M.A = 3
Answer:
- The answer is the concentration of an NaOH = 1.6 M
Explanation:
The most common way to solve this kind of problem is to use the formula
In your problem,
For NaOH
C₁ =?? v₁= 78.0 mL = 0.078 L
For H₂SO₄
C₁ =1.25 M v₁= 50.0 mL = 0.05 L
but you must note that for the reaction of NaOH with H₂SO₄
2 mol of NaOH raect with 1 mol H₂SO₄
So, by applying in above formula
- (C₁ * 0.078 L) = (2* 1.25 M * 0.05 L)
- C₁ = (2* 1.25 M * 0.05 L) / (0.078 L) = 1.6 M
<u>So, the answer is the concentration of an NaOH = 1.6 M</u>
The answer is neutrons and protons.
Hope you got it!!
