Ask question

Ask question

All categories

2 years ago

12

Explain this question in summary

1 answer:

pickupchik [31]2 years ago

3 0

Answer:

in region AB the body was not moving

in region BC the body was moving forward with a increasing velocity therefore accelerating constantly

in region CD the body was moving with a constant velocity hence zero acceleration

in region DE the body was moving backwards decelerating

You might be interested in

Explain how and why water travels through the four Earth systems as it moves through the water cycle

Nostrana [21]

Water in the Earth system is influencing all aspects of life on Earth. ... The returning water falls directly back into the oceans, or onto land as snow or rain. It soaks into the soil to move into the groundwater or runs off the Earth's surface in streams, rivers and lakes, which drain back into the oceans.

6 0

3 years ago

You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.

dem82 [27]

Angle (θ) = 60°
Force (F) = 20 N
Distance (s) = 200 m
Therefore, work done
= Fs Cos θ
= (20 × 200 × Cos 60°) J
= (20 × 200 × 1/2) J
= (20 × 100) J
= 2000 J

<u>Answer</u><u>:</u>

<u>2</u><u>0</u><u>0</u><u>0</u><u> </u><u>J</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0

2 years ago

Read 2 more answers

4. A train starts its journey and accelerates at 5 ms 2. How long does it take for it to reach a velocity of 100 ms??

Agata [3.3K]

Answer:

20 seconds

Explanation:

6 0

4 years ago

Read 2 more answers

Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another

Tanya [424]

Answer: $I_2=0.618\times 10^{-7} W/m^2$

Explanation:

Given

Distance between source and receiver $d_1=3 m$

Sound Intensity $I_1=1.1\times 10^{-7} W/m^2$

Distance of of second observer $d_2=4 m$

Intensity varies as

$I\propto \frac{1}{d^2}$

using this

$I=\frac{k}{d^2}$

$\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}$

$\frac{1.1\times 10^{-7}}{I_2}=\frac{4^2}{3^2}$

$I_2=0.75^2\times 1.1\times 10^{-7}$

$I_2=0.618\times 10^{-7} W/m^2$

6 0

3 years ago

Maaf sebelumnya ,bisa minta tolong kerjakan tugas saya? saya harus mengerjakan tugas Fisika yang lain . tolong bantu 4 nomer saj

AlladinOne [14]

Sorry cant not answer this question

8 0

3 years ago