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Dahasolnce [82]

2 years ago

10

Maaf sebelumnya ,bisa minta tolong kerjakan tugas saya? saya harus mengerjakan tugas Fisika yang lain . tolong bantu 4 nomer saj

a .

1 answer:

AlladinOne [14]2 years ago

8 0

Sorry cant not answer this question

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Can someone help me with this question

monitta

Answer:

hypothesis , hope it helps

Explanation:

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Why are we buried in the ground when we die?

trasher [3.6K]

What kind of the question is that. We aren't really buried. We either go to Heaven or the other place. Some people say it's over when your buried in the ground but believers don't really think that.

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2 years ago

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How can the frequency with which the direction of a current changes be regulated?

sesenic [268]

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In an inductive circuit, when frequency increases, the circuit current decreases and vice versa.

Explanation:

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2 years ago

If the man pushes with a force of 2000N and friction is 500N, what is the resultant force?

alexandr402 [8]

Answer:

Explanation:

If the force of 2000 N is directed towards the right and the friction is directed towards the left, the 2000 N force is positive and the other is negative. To find the resultant force:

2000 - 500 = 1500 N to the right

3 0

2 years ago

One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit

nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

$\lambda$ = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

$\theta=\dfrac{1.22\lambda}{D}$

The width is given by

$d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m$

The required width is 0.000003782 m

Minimum resolvable line separation is given by

$\dfrac{0.000003782}{2}=0.000001891\ m$

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when $\lambda=157\ nm$

$d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m$

The new minimum resolvable line separation between adjacent lines is

$\dfrac{0.00000239425}{2}=0.000001197125\ m$

6 0

3 years ago