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harina [27]
3 years ago
5

How scientists decide if an exoplanet might be like Earth?

Physics
1 answer:
boyakko [2]3 years ago
4 0
With their stars habitable zone, but that depends the a range of factors such as,temperatures,available water,composition,stable climate etc...
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While helping an astronomy professor, you discover a binary star system in which the two stars are in circular orbits about the
svetoff [14.1K]

Answer:

The value is d =  3.66 *10^{10} \  m

Explanation:

From the question we are told that

The orbital period is T =  31.3 \ days = 31.3 * 86400 = 2704320 \ s

Generally for the centripetal force acting one of the stars will be equal to the gravitational force between the stars and this can be mathematically represented as

F_g  =  F_c

=> \frac{Gm*m}{d^2} =  \frac{mv^2}{r}

Here m represents the mass of each star given that they have same mass and this equal to the mass of the sun whose value is

m  =  1.989*10^{30} \  kg

d(2 * r) is the diameter of the orbit which is distance between each star

r is the radius of the orbit

G is the gravitational constant with value G= 6.67*0^{-11} \  m^2/kg \cdot s^2

v is the velocity of the stars which can be mathematically represented as

v  =  \frac{2 \pi r}{T}

So

\frac{Gmm }{(2 * r)^2}  = \frac{m (\frac{2\pi r}{T} )^2}{r}

=> r =[  \frac{Gm T^2}{16 \pi ^2} ]^{\frac{1}{3} }

=> r =  [\frac{6.67 *10^{-11} * (1.989 *10^{30}) * 2704320^2}{16 * (3.142)^2} ]^{\frac{1}{3} }

=> r =  1.83 *10^{10} \  m

Generally the distance between the star is

d =  2 * r

=> d =  2 * 1.83 *10^{10}

=> d =  3.66 *10^{10} \  m

3 0
3 years ago
If the average frequency emitted by a 160 W light bulb is 5.00 1014Hz and 10.0 of the input power is emitted as visible light ap
bearhunter [10]

Answer:

The value is \frac{n}{t}  = 4.83 *10^{19} \  photons / s

Explanation:

From the question we are told that

   The power rating of the bulb is  P = 160 \ W

   The frequency is f =  5.00 *10^{14} \ Hz

   The percentage of the input power that is emitted as visible light is \eta =  10\% = 0.10

   

Generally the amount of power emitted as visible light is mathematically represented as

       P_l =  0.10 * P_i

=>  P_l =  0.10 *160

=>  P_l =  16 \ W

Generally the amount of energy emitted as light is mathematically represented as

        E = n *  h  *  f

Here n is the number of photon ,  h is the Planks constant with value h =  6.625*10^{-34} \  J\cdot s

Generally this power emitted as visible light is mathematically represented as

   P_l = \frac{E}{t}

=>  P_l = \frac{E}{t} = \frac{nhf}{t}

=>  \frac{n}{t}  = \frac{P_l }{hf}

=>  \frac{n}{t}  = \frac{16 }{6.625 *10^{-34}* (5.00*10^{14})}

=>  \frac{n}{t}  = 4.83 *10^{19} \  photons / s

4 0
3 years ago
Describe the agronomic significance of the upper and lower plastic limits, and of the plasticity index?​
GarryVolchara [31]

Answer:It shows the size of the range of the moisture contents at which the soil remains plastic. In general, the plasticity index depends only on the amount of clay present. It indicates the fineness of the soil and its capacity to change shape without altering its volume.

4 0
3 years ago
What is an unstable nucleus emits
Aleksandr-060686 [28]

Answer:

Explanation:

Unstable nucleus tends to emit small particles of matter(alpha or beta particles) with an attendant emission of electromagnetic radiation and some amount of energy.

For every atomic nucleus, there is a specific neutron/proton ratio which ensures stability of the nucleus.

Any nucleus with a neutron/proton combination different from its stability ratio (i.e either too many neutrons or too many protons) will be unstable and split.

The will emit some small particles and radiations until they become stable.

8 0
3 years ago
Which chemicals are major contributors to ozone layer destruction? Select two answer choices.
Nastasia [14]

Answer:

what are the answers to select? or do you just say them

Explanation:

???

3 0
3 years ago
Read 2 more answers
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