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amid [387]
2 years ago
5

Determine whether each of the following sequences are arithmetic, geometric or neither. If arithmetic, state the common differen

ce. If geometric, state the common ratio. -29, -34, -39, -44, -49, ...
Is this: common difference =5?
arithmetic?
Mathematics
2 answers:
Andru [333]2 years ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Let's see if the sequence is Arithmetic :}

\textsf{If the difference between successive terms is } \textsf{equal then, the terms are in AP}

  • \textsf{-34 - (-29) = -5 }

  • \textsf{-39 - (-34) = -5 }

\textsf{Since the common difference is same, } \textsf{we can infer that it's an Arithmetic progression} \textsf{with common difference of -5}

BartSMP [9]2 years ago
3 0

Sequence: -29, -34, -39, -44, -49, ...

<u>First we need to identify the </u><u>terms</u>:

  • 1st term = -29
  • 2nd term = -34
  • 3rd term =  -39
  • 4th term = -44
  • 5th term  = -49

If the sequence is arithmetic, \boxed{\sf \bold{second \ term = \dfrac{first \  term+third \ term}{2} }}

If the sequence is geometric, \boxed{\sf \bold{second \ term = \sqrt{first \ term \ x  \ third \ term} }}

=======================================

Check for arithmetic

\rightarrow \sf -34 = \sf \dfrac{-29 +(-39)}{2}

\rightarrow \sf -34 = \sf \dfrac{-68}{2}

\rightarrow \sf -34 = -34       [<u>Hence it's arithmetic series</u>]

To find common difference. we have to think of how to go to next term.

first term: -29

<u>to go the second term, subtract by -5</u>

-29 -5 = -34, second term

-34 - 5 = -39, third term

Hence, common difference: <u>-5</u>

<u>Solutions</u>:

Arithmetic Sequence

Common Difference: -<u>5</u>

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3 years ago
A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 p
Alona [7]

Answer:

250 minutes of calling will cost same using both plans.

$53

Step-by-step explanation:

Please consider the complete question.

A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 plus an additional $0.14 of each minute of calls.  For what amount of calling do the two plans cost the same?  What is the cost when the two plans cost the same?

Let x represent the number of call minutes.

The total cost of calling for x minutes using plan A would be cost of x minutes plus fixed charge that is 0.12x+23.

The total cost of calling for x minutes using plan B would be cost of x minutes plus fixed charge that is 0.14x+18.

To find the number of minutes for which both plans will have same cost, we will equate total cost of x minutes for both plans and solve for x.

0.14x+18=0.12x+23

0.14x-0.12x+18=0.12x-0.12x+23

0.02x+18=23

0.02x+18-18=23-18

0.02x=5

\frac{0.02x}{0.02}=\frac{5}{0.02}

x=250

Therefore, calling for 250 minutes will cost same using both plans.

Upon substituting x=250 in expression 0.14x+18, we will get:

0.14(250)+18=35+18=53

Therefore, the cost will be $53, when the two plans cost the same.

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3 years ago
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Answer:

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Step-by-step explanation:

Multiply -4 and x and -4 and 5. It has infinite solutions

3 0
3 years ago
drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w
GenaCL600 [577]

Answer:

95% Confidence interval:  (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

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\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

7 0
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