A 6.0 kg rock falls from a cliff and hits the ground at 32.5 m/s. a) Determine the kinetic energy. b) How much potential energy
did it have before it fell? C) How much mechanical energy does it have before it hits the floor? Please answer all three.
1 answer:
Answer:
See below
Explanation:
KE = 1/2 m v^2 = 1/2 *6 * 32.5^2 = 3168.75 j
PE = mgh = KE at end = 3168.75 j
ME = 3168.75 j
ME is KE + PE at any point
before it falls it has no KE before it hits it has no PE
so ME = 3168.75 j
You might be interested in
Answer:
It is Conductivity because it is the measure of the ease.
Weight tending to shear the pin is
W = 24.0 N
The shear area of the pin is
A = (π/4)*(2.0 x 10⁻³ m)² = 3.1416 x 10⁻⁶ m².
The shear stress is
τ = (24.0 N)/(3.1416 x 10⁻⁶ m²)
= 7.64 x 10⁶ Pa
= 7.64 MPa
Answer: 7.64 Mpa
Answer:
0.1667Hz
Explanation:
by explanation frequency is given by 1/time
after carrying out the calculation of time we can easily get frequency.
time=speed/distance
=18/3
=6s
but frequency=1/time
hence=1/6
=0.1667hertz
The answer is reverse faults.
Astronomers use the doppler effect to study the motion of objects across the Universe.
