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Firdavs [7]
3 years ago
9

If the magnet is now pushed into the coil and then held stationary inside the coil describe fully what would you observe on the

galvaromoter?​
Physics
1 answer:
alexira [117]3 years ago
8 0

Answer:

E = q V B     describes the electric field induced

E Proportional to V B

while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)

If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly

When V drops to zero the deflection must again be zero

So one would see a blip due to the deflection of the galvanometer

Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)

B always increases to a constant value because of the properties of the magnet.

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Answer:

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3 years ago
The slope of a velocity time graph will give___
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Answer:

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If the amount of gas in a sealed container increases, what happens to the pressure in the container
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3 years ago
Read 2 more answers
A 12-kg projectile is launched with an initial vertical speed of 20 m/s. It rises to a maximum height of 18 m above the launch p
kirill115 [55]

Answer:

Change in mechanical energy, \Delta E=283.2\ J

Explanation:

It is given that,

Mass of the projectile, m = 12 kg

Speed of the projectile, v = 20 m/s

Maximum height, h = 18 m

Initially, the projectile have only kinetic energy. it is given by :

K=\dfrac{1}{2}mv^2

K=\dfrac{1}{2}\times 12\ kg\times (20\ m/s)^2

K = 2400 J

Finally, it have only potential energy. it is given by :

P = mgh

P=12\ kg\times 9.8\ m/s^2\times 18\ m

P =2116.8 J

The change in mechanical energy is given by :

\Delta E=K-P

\Delta E=2400-2116.8

\Delta E=283.2\ J

So, the change in mechanical energy is 283.2 J. Hence, this is the required solution.

8 0
3 years ago
In the graph above, what is the instantaneous speed of the object after the first five seconds?
alexdok [17]

Answer:

D) 25 m/s

Explanation:

In order to solve this problem we must use the following kinematics equation.

v_{f} =v_{i} +(a*t)\\

where:

Vf = final speed [m/s]

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t = time = 5[s]

After 5 seconds the acceleration is equal to 5 [m/s^2]

Now replacing the values in the equation:

Vf = 0 + (5*5)

Vf = 25[m/s]

8 0
3 years ago
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