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Firdavs [7]
3 years ago
9

If the magnet is now pushed into the coil and then held stationary inside the coil describe fully what would you observe on the

galvaromoter?​
Physics
1 answer:
alexira [117]3 years ago
8 0

Answer:

E = q V B     describes the electric field induced

E Proportional to V B

while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)

If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly

When V drops to zero the deflection must again be zero

So one would see a blip due to the deflection of the galvanometer

Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)

B always increases to a constant value because of the properties of the magnet.

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FromTheMoon [43]

Answer:

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Explanation:

Credit goes to @naeAF

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5 0
3 years ago
A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. what is the average power delivered by the engine? (1 hp = 746 w)
AVprozaik [17]
The solution for this is:
Work done = force * distance = m*a*d and power = energy/time 
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5 0
3 years ago
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A particular car can go from rest to 90 km/h in 10 s. What is its acceleration? (Report your answer in km/h*s)
Romashka-Z-Leto [24]

Answer: 9 km/h

Explanation:i’m pretty sure

5 0
4 years ago
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Will give brainliest! A team of engineers is asked to evaluate several different
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6 0
3 years ago
Let A^=6i^+4j^_2k^ and B= 2i^_2j^+3k^. find the sum and difference of A and B​
andreyandreev [35.5K]

Explanation:

Let \textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}} and \textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}

The sum of the two vectors is

\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}

= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}

The difference between the two vectors can be written as

\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}

= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}

8 0
3 years ago
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