All categories

4 years ago

A 24.0N picture hangs from a nail in the wall. The diameter of the nail is 2.00 mm. The shear stress on the nail is

1 answer:

8 0

Weight tending to shear the pin is
W = 24.0 N
The shear area of the pin is
A = (π/4)*(2.0 x 10⁻³ m)² = 3.1416 x 10⁻⁶ m².

The shear stress is
τ = (24.0 N)/(3.1416 x 10⁻⁶ m²)
= 7.64 x 10⁶ Pa
= 7.64 MPa

Answer: 7.64 Mpa

You might be interested in

The model below shows a carbide ion. 8 light grey and 6 dark grey balls sit at the center with 2 concentric black rings around t

azamat

Answer:

This carbide ion change into a neutral carbon atom.

Explanation:

Given that,

Light grey balls = 8

dark grey balls = 6

medium grey balls = 2

Charge on dark grey ball = +1

Charge on light grey ball = 0

Charge on medium grey ball = -1

We need to change this carbide ion to a neutral carbon atom

Using given data

A dark grey ball has one positive charge. It means, it is a proton.

A light grey ball has has zero charge. It means, it is a neutron.

A medium grey ball has one negative charge.It means, it is a electron.

We know that,

The number of proton and number of electron is equal in a neutral atom.

So, No charge is present on the given model of atom.

Therefore, we can say that the atom is neutral.

We know that,

The sum of total number of protons presents in an atom it is called atomic number.

So, The total number of protons is 8, the total number of electrons is 8 and the total number of neutrons is 9 in given atom.

Hence, This carbide ion change into a neutral carbon atom.

6 0

4 years ago

Any 3 differences between telescope and microscope

Keith_Richards [23]

An instrument used to observe or imagine very small object using an optical mangifier
mirco cell.
Telescope is a magnifer of distance object

4 0

4 years ago

Someone help me with letter d. and e. I’m supposed to solve for y.

Bumek [7]

Answer:

$t=\frac{a}{\sqrt{1-\frac{y^2}{c^2}}}\\\frac{y^2}{c^2}=1-\frac{a^2}{t^2}\\y^2=\frac{c^2t^2-c^2a^2}{t^2}\\y=\frac{c}{t}\sqrt{t^2-a^2}$

$t=\frac{a}{\sqrt{1-\frac{v^2}{y^2}}}\\\frac{v^2}{y^2}=1-\frac{a^2}{t^2}\\\\\frac{v^2}{y^2}=\frac{t^2-a^2}{t^2}\\y^2=\frac{v^2t^2}{t^2-a^2}\\y=\frac{vt}{\sqrt{t^2-a^2}}$

7 0

3 years ago

pls help asap Create a Punnett square to model asexual reproduction of bacteria with the dominate trait T, recessive trat t. Cre

JulsSmile [24]

Ok you need a punnett square? its gonna be easy, create the square first, Then put the letters in their, When done message me

5 0

4 years ago

Which of the following quantities is measured by the area under the velocity time graph? (a) Magnitude of velocity (b) Magnitude

bearhunter [10]

Answer:

magnitude of displacement

5 0

3 years ago