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zheka24 [161]
2 years ago
13

25 POINTS + BRAINLIEST

Mathematics
1 answer:
klio [65]2 years ago
4 0

Answer:

C: 181,440

Step-by-step explanation:

P(n,r)=P(9,7)

=9!(9−7)!

= 181440

-lukelaws

Hope I helped if I did please mark me brainliest!

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PLEASE HELP!!!!!!!!!!!!!
Anna35 [415]
4y^2+2=(4y\cdot4y)+2\\
4y^2+2=16y^2+2 \leftarrow \text{not identity}\\\\
4y^2+2=(4y+y)+2\\
4y^2+2=5y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y+y)+2\\
4y^2+2=8y+2 \leftarrow \text{not identity}\\\\
4y^2+2=4(y\cdot y)+2\\
4y^2+2=4y^2+2 \leftarrow \text{identity}

So it's D.
8 0
4 years ago
Simplify the expression.
kotegsom [21]

Answer:

\large\boxed{D.\ 2x^2y\sqrt[5]{7xy^3}}

Step-by-step explanation:

\sqrt[5]{224x^{11}y^8}\\\\=\sqrt[5]{(32)(7)x^{5+5+1}y^{5+3}}\\\\\text{use}\ a^na^m=a^{n+m}\\\\=\sqrt[5]{(2^5)(7)x^5x^5x^1y^5y^3}\\\\\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[5]{2^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{y^5}\cdot\sqrt[5]{7xy^3}\\\\\text{use}\ \sqrt[n]{a^n}=a\\\\=2\cdot x\cdot x\cdot y\cdot\sqrt[5]{7xy^3}\\\\=2x^2y\sqrt[5]{7xy^3}

6 0
3 years ago
Let f(x) = 5x + 6 and g(x) = -7x - 4. <br> Find f(x) + g(x)
sattari [20]
5x + 6 + (-7x - 4)

5x + 6 - 7x - 4

-2x + 2
4 0
4 years ago
Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \  \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

Hope this helps!
5 0
3 years ago
Tell whether the statement is always, sometimes, or never true. The LCM of two different prime numbers is their product.
Blizzard [7]

Answer:

Step-by-step explanation:The LCM of two or more prime numbers is equal to their product. ... Assume two prime numbers as two different variables and find their LCM using prime factorization of both the numbers.

3 0
3 years ago
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