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2 years ago

25 POINTS + BRAINLIEST

Mathematics

1 answer:

klio [65]2 years ago

4 0

Answer:

C: 181,440

Step-by-step explanation:

P(n,r)=P(9,7)

=9!(9−7)!

= 181440

-lukelaws

Hope I helped if I did please mark me brainliest!

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75% of n is 45. n is what percent of 90?

Law Incorporation [45]

Answer:

66.67%

Step-by-step explanation:

75 /100 = .75

.75n = 45

45/.75 = 60

60 is n

60/90 = .666667

.666667 * 100 = 66.67%

3 0

3 years ago

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In the fallowing diagram, it is shown that mEHG is a right angle, mEHF = x+ 1 and mGHF = 5x+5. Find the value of x, the numerica

GalinKa [24]

Answer:

x = 14

EHF = 15 degree GHF = 75 degree

Step-by-step explanation:

(x+1) + (5x+5) = 90

(x+5x)+ (1+5) = 90

6x + 6 = 90

6x = 90-6

6x = 84

x = 84/6

x = 14

EHF + GHF = 90 degree

EHF = x+1

= 14 + 1 = 15

= 15 degree

GHF = 5x+5

= 14 x 5 (+5) = 70 + 5

= 75 degree

EHF = 15 degree GHF = 75 degree

4 0

3 years ago

1) Factor the polynomial using the GCE.<br> 2x2 + 6x

yarga [219]

Answer:

$2x(x+3)$

Step-by-step explanation:

$2x^{2} +6x$

$2x(x+3)$

4 0

3 years ago

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PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP PLS PLS HELP ASAP THANKS

Ipatiy [6.2K]

Answer:

I believe the answer is B. 15/5 = n/12

Step-by-step explanation:

Once again same method as I've explained before. However, this one tricked me a little bit and still is because of the appearance of the smaller triangle. However, If I don't focus on that I believe this answer is correct. This is because in order to find the missing side we need to find the factor of which the triangle was expanded. So we must divide a given side of the bigger triangle by the same similar side of the little triangle, like 15/5. Then we must divide n by its similar side which the appearance made me think 13 which is not an option so I believe it is 12 and it was just trying to throw me off. So n/12. Therefore that is why I believe B is correct.

7 0

2 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago