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2 years ago

Please solve and show your work

Mathematics

2 answers:

malfutka [58]2 years ago

7 0

I r d k sorry ghhfdhjh hhhhj

yaroslaw [1]2 years ago

5 0

Answer:

791.28

Step-by-step explanation:

1. 3.14*9²=254.34

2. 3.14*9*19=536.94

3. 536.94+254.34=791.28

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How do you do this I am so confused please help me

jok3333 [9.3K]

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3 years ago

What is the first step you would take to solve the equation 1 1/2 + 2 1/3 = ?

sineoko [7]

The first step to solve the equation 1 1/2 + 2 1/3 = ? is (a) First, you should convert the mixed numbers to improper fractions.

<h3>How to determine the first step?</h3>

The equation is given as:

1 1/2 + 2 1/3 = ?

The terms in the equation are mixed numbers.

So, the first stem is to convert the mixed numbers to improper fractions

Hence, the true statement is (a) First, you should convert the mixed numbers to improper fractions.

Read more about fractions at:

brainly.com/question/1622425

7 0

2 years ago

Could I get the answer, all work and explanation for this problem?

ratelena [41]

Okay so this is how i did it but idk if it’s right.
so i multiples the top and bottom by square root of 3 to get rid of the square root of 3
then i was left with 8-1/2(1) and got 7/2

8 0

3 years ago

9 1/3 divided by 2/3

Citrus2011 [14]

14 is the correct answer

6 0

3 years ago

Read 2 more answers

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago