1.
In line with the test each person who came into interaction
with the infected person will become infected also. With this information, the
calculation would be: 9 people each day for 7days would be equivalent to 9 x 7
which equals 63 people.
2.
Here were 7 other people in the experiment if patient
zero is left out. If each person intermingled with 6 different people every day
in 7 days then the calculation would be: 7 people infected x 6 new people = 42
infected people each day
42 new people every day x 7 days = 294
infected persons.
Answer:
P ( -1 < Z < 1 ) = 68%
Step-by-step explanation:
Given:-
- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :
u = 67.2
s.d = 4.6
- The random variable (X) that denotes standardized test scores following normal distribution:
X~ N ( 67.2 , 4.6^2 )
Find:-
What percent of the data fell between 62.6 and 71.8?
Solution:-
- We will first compute the Z-value for the given points 62.6 and 71.8:
P ( 62.6 < X < 71.8 )
P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )
P ( -1 < Z < 1 )
- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:
P ( -1 < Z < 1 ) = 68%
P ( -2 < Z < 2 ) = 95%
P ( -3 < Z < 3 ) = 99.7%
Answer:
a. -4x(factor) 5 (term), b. both are factors, c. both are factors, d. all are factors, e. pq(factor) q(term) f. all are factors.
Step-by-step explanation:
Answer:See explanation
Step-by-step explanation:
Raghu investment = Rs 60,000
Nazar investment = Rs 100,000
Raghu profit = 1800
Nazar profit = 3000
Raghu invested Rs. 60000 and Nazar Rs. 100000. The ratio of their investments will be:
= 60000/100000
= 3/5
= 3:5.
The ratio of their profit will be:
= 1800/3000
= 3/5
= 3:5
Since we have identical ratio, we can then say that the investment and the profit are divided proportionally.
