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3 years ago

Determine the value of k that partitions a segment into a ratio of 1:4

1 answer:

3 0

1/5 is the value but all you do is take the first number which would be your numerator and add both the first and last number together to get your denominator

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Answer the question in the photo pls!

galben [10]

Answer:

6x + 2y

Step-by-step explanation:

3 0

2 years ago

Please solve it

Marizza181 [45]

XD no sé que decir E=mc2 lo siento.

4 0

3 years ago

102,119,107,113,110, x; mean 114

Rom4ik [11]

Answer:

x = 133

Step-by-step explanation:

First, determine what total sum would be needed for the mean to be 114. Do this by multiplying 114 by 6 (bc total number of values in data set includes the variable x).

114 x 6 = 684

Next, add the five known values to get a sum of 551.

Now, just: 684 - 551 = 133

For the mean to be 114, x must equal 133.

6 0

2 years ago

Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

5 0

2 years ago

Solve the system of equations.in this form: (x, y) -5y + 8x = -18 5y + 2x = 58

Gre4nikov [31]

If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
so (x, y) = (2, 10)

5 0

3 years ago

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