Answer:
Explanation: A boy sitting on a chair.. Assuming the boy has a weight of 50N and he sits on the chair. He will exert a downward force of +50N while the chair will exert an upward force of -50N. This shows that for every action there must be equal and opposite reaction.. Another example is when you recoil a gun
Answer:
.y₂ = 0.5704 m
, y2= 44.47 m,
Explanation:,
For this exercise we will use the kinematics relations
Ball
y₁ = y₀ + v₀₁ t
y₀ = 11.0 m
v₀₁ = 5.10 m / s
Pellet
y₂ = 0 + v₀₂ t - ½ g t²
V₀₂ = 39.0 m / s
At the meeting point the two bodies have the same height
y₁ = y₂
y₀ + v₀₁ t = v₀₂ t -1/2 g t²
11 + 5.1 t = 39 t - ½ 9.8 t²
4.9 t² - 33.9 t +11 = 0
.t2 - 6,918 + 2,245 = 0
t = [6,918 ±√ 6,918 2 - 4 2,245)] / 2
t = [6,918 ± 6.2356.] / 2
t₁ = 6.58 s
t₂ = 0.3412 s
Let's calculate the positions for each time
t₂ = 0.3412 s
y₂ = 39 t - ½ 9.8 t2
y₂ = 39 0.3112 - ½ 9.8 0.3412²
y₂ = 0.5704 m
.t1 = 6.58 s
.₂ = 39 6.58 - ½ 9.8 6.58 ^ 2
y2= 44.47 m
Answer:
the normal force
Explanation:
The free-body diagram represents all the forces acting on an object. In this example, there are four forces acting on the box: an applied force, the friction (which always act opposite to the applied force), the weight of the box (which is always downward), and the normal force.
The normal force is the reaction force exerted by the surface on which the box is moving on the box, and this reaction force is always opposite to the force exerted by the box on the surface. Since the latter is downward, it means that the normal force must be upward, so in the diagram it is wrong.
Answer:
<em>x=6.39 m</em>
Explanation:
<u>Rectangular Components of a Vector</u>
Vectors can be expressed in several forms, including the magnitude-angle form, and the rectangular-coordinates form.
If the magnitude r and angle β are given, we can find the rectangular coordinates (x,y) as follows:
The vector of the question has a magnitude of r=9.55 m and an angle β=-48°. The x-component is:
Using a digital calculator:
x=6.39 m
Answer:
Explanation:
In a rotating system , when a torque is applied , angular acceleration or deceleration takes place . The child is walking towards the center . He must be applying force on the ground . In return , ground must be applying reaction force on him which helps him to go towards the center . These two force of action and reaction are internal forces . One will increase the angular momentum of one and the other force will decrease the angular
momentum of other . But total angular momentum of the whole system will remain constant . So angular momentum will be conserved.