Answer:
168 Hz, 280 Hz and 392 Hz
Explanation:
The resonant frequencies for a closed pipe at one end is given by :
, n = 1,3,5...
The fundamental frequency, f₁ = v/4l = 56 Hz
For first overtone, put n = 3
For second overtone, put n = 5
For third overtone, put n = 7
So, the first three overtones are 168 Hz, 280 Hz and 392 Hz.
Answer:
the action of measuring something.
Answer:
the twenty-fourth, and last, letter of the Greek alphabet (Ω, ω), transliterated as ‘o’ or ‘ō.’.
Explanation:
The magnitude and sign of the charge are 0.8 MC and negative respectively.
To find the answer, we need to know about the electric potential of a point charge.
<h3>What's the mathematical expression of the electric potential of a point charge?</h3>
- Mathematically, the electric potential at a distance 'r' from a point charge 'q' is given as (Kq)/r.
- K is the electrical constant with value 9×10^(-9) in vaccum.
<h3>What will be the magnitude and sign of a charge, if potential is -3.50V at 2mm?</h3>
From the expression of electric potential, charge is
q= (potential ×r)/K
= (-3.5×0.002)/ (9×10^(-9))
= -0.8 mega coulomb.
Thus, we can conclude that the magnitude and sign of the charge are 0.8 MC and negative respectively.
Learn more about the electric potential here:
brainly.com/question/14306881
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Answer:
Explanation:
Electrical energy is the correct answer