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3 years ago

6

How do you find total pension expense?

1 answer:

chubhunter [2.5K]3 years ago

7 0

Answer:

Total periodic pension costs (TPPC) is equal to the contributions plus change in the pension liability during the year. Each period, the periodic pension cost is recognized in profit or loss (P&L) and/or in other comprehensive income (OCI).

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Simply the following 5 1/3 -7 5/6 + 6 1/4

lana66690 [7]

Answer:

$3 \frac{3}{4}\\$ / 3.75

Step-by-step explanation:

Step 1: Make all the mixed numbers, improper fractions:

$5 \frac{1}{3} = \frac{16}{3}$

$7\frac{5}{6} = \frac{47}{6}$

$6\frac{1}{4} =\frac{25}{4}$

In order to add/subtract fractions, they must all have a common denominator, the smallest common denominator for all these fractions is 12. And so in order to make 12 the denominator, we must now multiply all the fractions by their multiple.

$\frac{16}{3} = \frac{64}{12}$

$\frac{47}{6} = \frac{94}{12}$

$\frac{25}{4} = \frac{75}{12}$

Time to solve:

$\frac{64}{12} -\frac{94}{12} + \frac{75}{12} =$

$\frac{-30}{12} + \frac{75}{12} =$

$\frac{45}{12}$

Simplify:

$\frac{45}{12} = \frac{15}{4}$

Convert to a mixed number:

$3 \frac{3}{4}$

Hope this helps!

8 0

3 years ago

I know this question is kinda easy but I'm lazy so...

Misha Larkins [42]

Answer:

Hello,

Shirts = 28

Jackets = 32

Hope that this helps!

Step-by-step explanation:

4 0

3 years ago

Which of the following is equal to the rational expression.......

Alecsey [184]

Maybe it would be B
hope it helps

8 0

4 years ago

Read 2 more answers

Find the y-intercept of the line on the graph

nadezda [96]

4 is on the y-intercept. the y axis is vertical and the x axis is horizontal.

4 0

3 years ago

Read 2 more answers

The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit

forsale [732]

Answer:

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

$\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|$

(a)Mean

Expected Value, $\mu =\sum x_iP(x_i)$

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

Mean=0.26

(b)Standard Deviation

$(x-\mu)^2\\(0-0.26)^2=0.0676\\(1-0.26)^2=0.5476\\(2-0.26)^2=3.0276\\(3-0.26)^2=7.5076$

Standard Deviation $=\sqrt{\sum (x-\mu)^2P(x)}$

$=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765$

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

3 0

3 years ago