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3 years ago

Use the drop-down menus to complete the sentences describing what happens when the temperature of a fluid

Chemistry

2 answers:

Anton [14]3 years ago

8 0

Answer:

increases

decreases

rises

Explanation:

Scorpion4ik [409]3 years ago

5 0

when the temperature of a fluid increases the kinetic energy of the molecules increases.

<u>Explanation:</u>

when there is a change in liquid temperature then there will be changes in its properties especially in the (KE) kinetic energy of molecules and the density of the fluid.
Due to the addition of the heat kinetic energy of the fluid molecules as it gains the heat, the intermolecular movement increases so there will be in the increased collision between the molecules which results in breaking the intermolecular force.
Whenever the heat is applied to any matters nature is to tend to expand so the fluids also expand which results in the decrease in the density of the liquid.
And also due to the increases in the kinetic energy, the speed of the fluid also increases.

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1 year ago

Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

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3 years ago