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Vedmedyk [2.9K]
3 years ago
7

The first step in coal formation process is the formation of:

Chemistry
1 answer:
Reil [10]3 years ago
4 0
Do you have a picture of where you go this question from?
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fill in the blank: 1.)the amount of space that matter fills is its.................. 2.)a state of matter with a definite volume
marshall27 [118]
1) mass

2) gas

3) liquid

4) temperature

5) pressure
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3 years ago
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Please help urgent Balance the following word equation:
LekaFEV [45]

Answer:

AlCl3 + 3Na > Al + 3NaCl

Explanation:

AlCl3+Na → Al + NaCl

Al =1 Al=1

Cl =3 Cl = 1

Na=1. Na = 1

so balance

and it would be

Alcl3 + 3Na → Al + 3NaCl

8 0
3 years ago
Determine the mass of 10g of CaCO3​
NISA [10]

Answer:

= 100u. Hence 10 g = 0.1 mole. Hope it's helpful to u

3 0
2 years ago
What are 3 types of mutations
mote1985 [20]

1- Base substitutions.

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3 years ago
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Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con
arsen [322]

Answer:

a)  T_b=590.775k

b)  W_t=1.08*10^4J

d)  Q=3.778*10^4J

d)  \triangle V=4.058*10^4J

Explanation:

From the question we are told that:

Moles of N2 n=2.50

Atmospheric pressure P=100atm

Temperature t=20 \textdegree C

                      t = 20+273

                     t = 293k

Initial heat Q=1.36 * 10^4 J

a)

Generally the equation for change in temperature is mathematically given by

\triangle T=\frac{Q}{N*C_v}

  Where

  C_v=Heat\ Capacity \approx 20.76 J/mol/K

T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }

T_b-293k=297.775

T_b=590.775k

b)

Generally the equation for ideal gas is mathematically given by

 PV=nRT

For v double

 T_c=2*590.775k

 T_c=1181.55k

Therefore

PV=Wbc

Wbc=(2.20)(8.314)(1181_590.778)

Wbc=10805.7J

Total Work-done W_t

W_t=Wab+Wbc

W_t=0+1.08*10^4

W_t=1.08*10^4J

c)

Generally the equation for amount of heat added is mathematically given by

Q=nC_p\triangle T

Q=2.20*2907*(1181.55-590.775)\\

Q=3.778*10^4J

d)

Generally the equation for change in internal energy of the gas is mathematically given by

\triangle V=nC_v \triangle T

\triangle V=2.20*20.76*(1181.55-293)k

\triangle V=4.058*10^4J

3 0
2 years ago
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