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2 years ago

Some water released 7800 J of energy when cooled from 78°C to 33°C. What was the mass of the water?

Chemistry

1 answer:

Karo-lina-s [1.5K]2 years ago

4 0

Answer:

-41. 47

Explanation:

m = q / Cp x T

m = Mass

q = Energy (or joules)

Cp = Heat Capacity

T = Change in Temperature

Water's heat capacity is always 4.18.

This is the formula you'll need for change in temperature:

Final - Initial

So, 33 - 78 = -45

m = 7800 / 4.18 x -45

= -41.47

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3 years ago

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Explanation:

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$E = m \cdot c^{2}$ ,

where

$E$ stands for energy,
$m$ stands for mass, and
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Thus, proceed with the speed of light in SI units. The SI unit for speed is meters per second. For the speed of light, $c \approx \rm 3.00\times 10^{8}\;m\cdot s^{-1}$ .

Apply the mass-energy equivalence:

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