Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)
Answer:
1) synthesis MgI2
2) double replacement CuS + (HCl)2
3) double replacement, not sure ab the formula sorry
Answer:
<h3>The answer is 3.0 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 15 g
volume = 5 mL
We have
We have the final answer as
<h3>3.0 g/mL</h3>
Hope this helps you
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