Answer:
A) 8.00 mol NH₃
B) 137 g NH₃
C) 2.30 g H₂
D) 1.53 x 10²⁰ molecules NH₃
Explanation:
Let us consider the balanced equation:
N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)
Part A
3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

Part B:
1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

Part C:
According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

Part D:
6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

Explanation:
Volume is the quantity of three-dimensional
8 valence electrons are found in noble gases. Since noble gases have 8 valence electrons that means they have a full shell - which makes them unreactive
Answer:
1.0 L
Explanation:
Given that:-
Mass of
= 
Molar mass of
= 64.099 g/mol
The formula for the calculation of moles is shown below:

Thus,


According to the given reaction:-

1 mole of
on reaction forms 1 mole of 
0.0396 mole of
on reaction forms 0.0396 mole of 
Moles of
= 0.0396 moles
Considering ideal gas equation as:-

where,
P = pressure of the gas = 742 mmHg
V = Volume of the gas = ?
T = Temperature of the gas = ![26^oC=[26+273]K=299K](https://tex.z-dn.net/?f=26%5EoC%3D%5B26%2B273%5DK%3D299K)
R = Gas constant = 
n = number of moles = 0.0396 moles
Putting values in above equation, we get:

<u>1.0 L of acetylene can be produced from 2.54 g
.</u>