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larisa [96]
2 years ago
5

What is the solution set of 2/5 (x+4) -3/5 (2x+3) = 2/5(2-x)-1​

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0

Step-by-step explanation:

2/5(x+4) - 3/5(2x+3) = 2/5(2-x)-1

2/5(x+4)-3/5(2x+3) = 2/5x-1/1(2-x)

2/5(x+4)-3/5(2x+3) = -2/5(2-x)

2/5x+8/5 - 6x/5 + 9/5 = -4/5 - (-2x/5) (-x- = +)

2x/5 + 8/5 - 6x/5 + 9/5 = -4/5 + 2x/5

(take like terms)

2x/5 - 6x/5 - 2x/5 = -4/5 - 9/5 - 8/5

( Find their L.C.M ) (5 is the LCM)

2x - 6x -2x / 5 = -4 - 9 - 8 / 5

-10x / 5 = -13 / 5

( cross multiply)

-50x = -65

x = -65/50

x = -1.3 ( decimal)

or x = 13/10 (improper fraction)

or x = 1 ³/10 ( mixed fraction).

Hope this helps.

Good luck.

If you have any questions, you're free to ask.

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Answer: 0.5049

Step-by-step explanation:

The probability that the first card drawn is a heart is 13/52 = 1/4

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Oduvanchick [21]
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Step 3: 3x cancels out with -3x
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Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

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3 years ago
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