Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
6n/6=2/6
n=0.333333…
Or rounded to 0.3 in decimal form and 1/3 in fraction form
Answer:
118.3 m²
Step-by-step explanation:
Step 1. Calculate the <em>semiperimeter</em> (s).
s = (p + q + r)/2
s = (17 + 18+ 15)/2
s = 50/2
s = 25 m
===============
Step 2. Calculate the <em>area</em> (A).
Use <em>Heron’s formula</em>:





A = 118.3 m²
Answer:
Step-by-step explanation:
If you had a solid cylinder, in order to find the amount of material that makes up that solid cylinder, you would find the volume using the radius of 4 (half of the diameter 8). BUT we want to know the volume of the solid with the radius of 4 minus the solid that has a radius of 2.5 (half of the diameter 5).
That's volume outer - volume inner. To find the outer volume:
so
and
and do the same for the inner volume:
and

Subtract the inner from the outer:

If you need your answer in decimal form, then the volume is
9189.16 cm³
Answer:
On average, the workers dig 4.75ft each day. Also, what x and y questions?
Step-by-step explanation:
Take 
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