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2 years ago

11

Its asking to expand and simplify an expression for the area of this rectangle.

2 answers:

Anettt [7]2 years ago

7 0

Answer:

4x^2 + 11x - 20

Step-by-step explanation:

area is width X height
multiply the width (4x - 5) and the height(X + 4)
I always imagine a multiplication grid for this kind of problem, with X and +4 at the top and 4x and -5 going down, and then combine terms
you get 4x^2 + 11x - 20

atroni [7]2 years ago

5 0

Answer:

(4x-5)(x+4)

4x squared- 16x -5x - 20
4x squared-21x - 20

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Rewrite in simplest terms : <br> 9(-8d - 7 ) +6(d+7)

Pepsi [2]

Answer: -66d-21 I think.

Step-by-step explanation:

9(-8d-7<u>)</u>+6(d+7)

-72d-63+6d+42 Distributive Property

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-66d-21 Answer

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3 years ago

Students in grades 7 and 8 were asked which food they liked the best. The results are shown in the table. What percentage of all

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Answer:

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Step-by-step explanation:

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3 years ago

What would be the appropriate units and intervals to use along the x- and y-axes

Vika [28.1K]

X axes are supposed to be positive and the y is negative.

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3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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3 years ago

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Amiraneli [1.4K]

Answer:

I think it would be c 160

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers