perimeter = 2L+2w
from the problem L = 1/5w-2
so perimeter = 2(1/5w-2) +2w
= 2/5w-4 +2w
=12/5w-4
without seeing your choices it should be similar to this
Answer:
23
Step-by-step explanation:
Let the measure of side AB be x, then, the measue of side AE is given by

.
Now, ABCD is a square of size x, thus the area of square ABCD is given by

Also, AEFG is a square of size

, thus, the area of square AEFG is given by

<span>The sum of the areas of the two squares ABCD and AEFG is given by

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
Answer:
what is the problem i can't see anything