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Brums [2.3K]
2 years ago
10

1. In a board game, students draw a number, do not replace it, and then draw a second number. Determine the probability of each

event occurring.
2 1 6 2
9 6 6 1

a. An odd number, then drawing a 6
b. A 2, then drawing another 2
c. A number divisible by 3, then drawing a 1 d. A 1, then drawing a 6
e. A prime number, then drawing a composite number
f. A 9, then drawing another 9
g. A 9, then drawing a number divisible by 1 h. An even number, then drawing 1 ​
Mathematics
1 answer:
serious [3.7K]2 years ago
4 0

Answer:

The probability of drawing a two and another 2 is 1/72.

Please Mark Brainliest If This Helped!

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Dmitriy789 [7]

Answer:

v = 0.58

Step-by-step explanation:

-22 - 7v = -3(8v + 4)

Expand -3(8v + 4)

3 * 8v - 3 * 4

Simplify -3 * 8v -3 * 4

= -24v - 12

-22 - 7v = -24v - 12

Add 22 to both sides

-7v = -24v +10

Add 24v to both sides

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v =\frac{10}{17}

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5 0
3 years ago
Consider the gender and class make-up of students at a large university by gender and status as given in the table.
azamat

Answer:

0.589

Step-by-step explanation:

THis is a conditional probability question. Let's look at the formula first:

P (A | B) = P(A∩B)/P(B)

" | " means "given that".

So, it means, the <u><em>"Probabilty A given that B is equal to Probability A intersection B divided by probability of B."</em></u>

<u><em /></u>

So we want to know P (Female | Undergraduate ). This in formula is:

P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)

Now,

P (Female ∩ Undergraduate) means what is common in both female and undergraduate? There are 43% female that are undergrads. Hence,

P (Female ∩ Undergraduate) = 0.43

Also,

P (Undergraduate) is how many undergrads are there? There are 73% undergrads, so that is P (undergraduate) = 0.73

<em>plugging into the formula we get:</em>

P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)

=0.43/0.73 = 0.589

this is the answer.

4 0
3 years ago
At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100
alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}

For a 95% CI, the value of z=1.96.

1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05

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