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aleksley [76]
3 years ago
9

I just need to know how to do it im just to lazy to look it up

Mathematics
2 answers:
aalyn [17]3 years ago
4 0

Answer:

x = 3

s = 11

z = 14

y = 2

Let me know if you need an explanation for this, I would be happy to help :)

777dan777 [17]3 years ago
4 0

Answer:

1. x = 3

2. s = 11

3. z = 14

4. y = 2

Step-by-step explanation:

1. x + 9 = 12

12 - 9 = x

⇒ x = 3

2. s - 1 = 10

10 + 1 = s

⇒ s = 11

3. 3 = z - 11

z - 11 = 3

11 + 3 = z

⇒ z = 14

4. 5 + y = 7

7 - 5 = y

⇒ y = 2

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What is the value of 3.85+0.004+0.117?
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If RX=4 and XS=9, then XT=<br> And how do you get it?
konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

RS^2=RT^2+TS^2

we have

RS=RX+XS=4+9=13\ units ---> by segment addition postulate

substitute

RT^2+TS^2=169  ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

RT^2=RX^2+XT^2

we have

RX=4\ units

substitute

RT^2=4^2+XT^2

RT^2=16+XT^2

XT^2=RT^2-16 ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

TS^2=XS^2+XT^2

we have

XS=9\ units

substitute

TS^2=9^2+XT^2

TS^2=81+XT^2

XT^2=TS^2-81 ----> equation C

step 4

equate equation B and equation C

TS^2-81=RT^2-16

TS^2-RT^2=81-16

TS^2-RT^2=65 ----> equation D

step 5

Solve the system

RT^2+TS^2=169 ----> equation A

TS^2-RT^2=65 ----> equation D

Solve by elimination

Adds equation A and equation D

RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117

Find the value of  RT^2

RT^2+117=169\\RT^2=52

step 6

Find the value of XT

equation C

XT^2=117-81\\XT^2=36\\XT=6\ units

7 0
3 years ago
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