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dem82 [27]
2 years ago
10

What are the solutions to the equation 3x2 + 15x = 18?

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
6 0

3x {}^{2}  + 15x = 18

<h2>Divide the entire thing by 3</h2>

x {}^{2}  + 5x = 6

x {}^{2}  + 5x - 6 = 0

<h2>You can find the roots by using the quadratic formula or by using the form x²-Sx+P</h2>

let \:  \alpha \:  and \: \beta  \: be \: the \: roots

<h2>Two numbers whose sum is -5 and product is -6</h2><h2>-6 and +1</h2>

<h2>Your answer is B</h2>

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Can someone please help me?
kvasek [131]

now, let's recall the rational root test, check your textbook on it.

so p  = 18 and q = 1

so all possible roots will come from the factors of ±p/q

now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.

recall that, a root will give us a remainder of 0.

let us use +3.


\bf x^4-7x^3+13x^2+3x-18 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{r|rrrrr} 3&1&-7&13&3&18\\ &&3&-12&3&18\\ \cline{1-6} &1&-4&1&6&0 \end{array}\qquad \implies (x-3)(x^3-4x^2+x+6)


well, that one worked... now, using the rational root test, our p = 6, q = 1.

so the factors from ±p/q are ±3, ±2, ±1

let's use 3 again


\bf \begin{array}{r|rrrrr} 3&1&4&1&6\\ &&3&-3&-6\\ \cline{1-5} &1&-1&-2&0 \end{array}\qquad \implies (x-3)(x-3)(x^2-x-2)


and of course, we can factor x²-x-2 to (x-2)(x+1).

(x-3)(x-3)(x-2)(x+1).

7 0
3 years ago
(awarding brainliest) PLS HELP ME i’m not that smart.
sleet_krkn [62]

Answer:

1. 43.98

2. 28.27

3. 7.85

Step-by-step explanation:

8 0
2 years ago
Can anyone help with this problem please ! i’m struggling with this question .
Serhud [2]

Answer:

2x=3

Step-by-step explanation:

Hope this helped.

7 0
3 years ago
Help me please I used all my points for this.
Paul [167]

Answer:

So easy just try your best if you cant contact me

5 0
2 years ago
Read 2 more answers
What is the y-value when x equals 25? y= 650 - 15(x)
yarga [219]

Answer:

y= 275 when x is 25

5 0
3 years ago
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