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VladimirAG [237]
3 years ago
12

C=0.41+0.26(z-1) solve for z

Mathematics
1 answer:
ddd [48]3 years ago
3 0
z = - 15-100c / 26 
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Pls Help!!!!! I will pick the brainiest answer as well. ;)
denpristay [2]

Answer:

49

Step-by-step explanation:

20+4=24 24+25=49

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Round 0.6203 to<br> the tenths place
navik [9.2K]

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0.6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
4 years ago
What is the greatest possible product of a 3-digit number and a 1 digit number
saw5 [17]
8,991 which is the product of 999 times 9
8 0
3 years ago
( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 =<br><br> Simplify the exponential expression
Korvikt [17]

Answer:

2

Step-by-step explanation:

\frac{(3*2)^4*3^{-3}}{2^3*3}

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4  * 2^4

\frac{3^4*2^4*3^{-3}}{2^3*3}

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1  are same

\frac{3^1*2^4}{2^3*3^1}

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2



4 0
4 years ago
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