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2 years ago

Juan is making a cake for his mom's birthday. For every three cups of

Mathematics

1 answer:

Vlad [161]2 years ago

4 0

Answer:

44 teaspoons

Step-by-step explanation:

33 divided by 3 is 11 and 4 x 11 is 44 if juan used 4 teaspoons of sugar every 3 cups of flour then 3 goes into 33 11 times and 4 x 11= 44

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Second part of the problem find the x. Link: https://brainly.com/question/26290433

Sliva [168]

Answer:

Step-by-step explanation:

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3 0

2 years ago

Simplify; l 81 -5/4 ! 256

pishuonlain [190]

Answer:

It's simple

Step-by-step explanation:

See what I did there? Simple?

5 0

3 years ago

A woman is randomly selected from the 18-24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally

dybincka [34]

Answer:

0.0274

Step-by-step explanation:

The mean is $\mu =114.8$ and the standard deviation is $\sigma =13.1.$

Calculate

$Z=\dfrac{X-\mu}{\sigma}$

for $X=140:$

$Z=\dfrac{140-114.8}{13.1}\approx 1.9237.$

If $X\sim N(114.8,\ 13.1),$ then $Z\sim N(0,1)$

and

$Pr(X>140)=Pr(Z>1.9237).$

Use table for normal distribution probabilities to get that

$Pr(Z>1.9237)=1-Pr(Z\le 1.9237)=1-0.9726=0.0274.$

7 0

3 years ago

Read 2 more answers

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago

Given that the sec A = 13/5 and A is in QIV, determine exact value for the sin A.

AysviL [449]

Answer:

The exact value of sin A is opp/hyp = -12/13

Step-by-step explanation:

If A is in Quadrant IV then the "opposite side" is negative and the "adjacent side" is positive. Since sec A = hyp / adj = 13 / 5 and since opp^2 + adj^2 must add up to hyp^2, Therefore y = √(hyp^2 - adj^2), or

y = -√(13^2 - 25) = -√144 = 12.

The exact value of sin A is opp/hyp = -12/13

6 0

3 years ago