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laila [671]
3 years ago
13

The height of the parallelogram, h, can be found by dividing the area by the length of the base. If the area of the parallelogra

m is represented by 4x2 – 2x + 5 and the base is 2x – 6, which represents the height? 2x + 5 + 2x – 7 – 2x – 7 + 2x + 5 –

Mathematics
2 answers:
tatuchka [14]3 years ago
6 0

Answer:

2x+5+\frac{35}{2x-6}

Step-by-step explanation:

Given,

The area of the parallelogram, A = 4x^2-2x+5

The length of its base, b = 2x-6

∵ The height of the parallelogram.

h=\frac{A}{b}

\implies h=\frac{4x^2-2x+5}{2x-6}

=2x+5+\frac{35}{2x-6}   ( by long division shown below )

Hence, the height of the given parallelogram is,

2x+5+\frac{35}{2x-6}

elena-s [515]3 years ago
4 0

Answer:

\frac{4x^{2}-2x+5}{2x-6} =2x + 5 + \frac{35}{2x-6}

Step-by-step explanation:

We know that the height of a parallelogram can be found by divind the area by the lenght of the base.

The area is 4x2 – 2x + 5 and the base is 2x – 6. To find the height, we need to divide both polynomials:

\frac{4x^{2}-2x+5}{2x-6} =2x + 5 + \frac{35}{2x-6}

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2 years ago
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lozanna [386]

Answer:

=\frac{27}{125}

Step-by-step explanation:

0.216

\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

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216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

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\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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2 years ago
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Sveta_85 [38]

The mode of a set of numbers is the number that occurs the most.

The numbers in this set are as follows,

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17 II

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So the mode of the set of numbers is 18!



3 0
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Step-by-step explanation:

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