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laila [671]
3 years ago
13

The height of the parallelogram, h, can be found by dividing the area by the length of the base. If the area of the parallelogra

m is represented by 4x2 – 2x + 5 and the base is 2x – 6, which represents the height? 2x + 5 + 2x – 7 – 2x – 7 + 2x + 5 –

Mathematics
2 answers:
tatuchka [14]3 years ago
6 0

Answer:

2x+5+\frac{35}{2x-6}

Step-by-step explanation:

Given,

The area of the parallelogram, A = 4x^2-2x+5

The length of its base, b = 2x-6

∵ The height of the parallelogram.

h=\frac{A}{b}

\implies h=\frac{4x^2-2x+5}{2x-6}

=2x+5+\frac{35}{2x-6}   ( by long division shown below )

Hence, the height of the given parallelogram is,

2x+5+\frac{35}{2x-6}

elena-s [515]3 years ago
4 0

Answer:

\frac{4x^{2}-2x+5}{2x-6} =2x + 5 + \frac{35}{2x-6}

Step-by-step explanation:

We know that the height of a parallelogram can be found by divind the area by the lenght of the base.

The area is 4x2 – 2x + 5 and the base is 2x – 6. To find the height, we need to divide both polynomials:

\frac{4x^{2}-2x+5}{2x-6} =2x + 5 + \frac{35}{2x-6}

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