This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):

$sin^{-1}[sin(2x+30)]=sin^{-1}(1)$

On the left, the inverse sin "undoes" or cancels the sin, leaving us with

2x + 30 = sin⁻¹(1)

The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:

2x + 30 = 90 and

2x = 60 so

x = 30

You're welcome!

4 0

2 years ago

The Sunday newspaper costs $2.10 issue delivered and the Saturday and weekday papers cost 40 cents per issue delivered how many

In-s [12.5K]

26 weeks is what I got

6 0

2 years ago

What is the equation of a line that passes through (4, 3) and has a slope of 2? y=2x−11 y=2x−7 y=2x−1 y=2x−5

LenaWriter [7]

Step-by-step explanation:

The coefficient of the x term repesents the slope of the graph.

So we have y = 2x +- ( ).

We have to find our number term, so let's substitute x = 4 and y = 3.

(3) = 2(4) +- ( )

3 = 8 +- ( )

To make this right, the number term must be -5.

3 = 8 - 5

So the equation is y = 2x - 5.

8 0

3 years ago

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