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Arte-miy333 [17]
2 years ago
11

A Ferris wheel has a radius of 80 feet. Two particular cars are located such that the central angle between them is 165º. To the

nearest tenth, what is the length of the intercepted arc between those two cars on the Ferris wheel?
Mathematics
1 answer:
Alex2 years ago
7 0

Answer: 230.4 feet

Step-by-step explanation:

arc length = circumfrance x fraction of a circle

                 = 2\pi r x \frac{165}{360}

                 = \frac{2*\pi *80*165  }{360}

                 = 230.4 feet to nearest tenth

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a water tank in the shape of a right rectanglar prism is 11 feet deep. the top of the water tank has an area of 220 square feet.
Simora [160]
 The Answer is 2420 ft^3
7 0
3 years ago
I’m confused on this one
Lorico [155]
The question is asking which of the following does not have side that are parallel. So which of them have lines that would never touch if they were never ending lines.
4 0
3 years ago
4. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7,
Bezzdna [24]

Answer:

187

Step-by-step explanation:

A number m is such that when it is divided by 30, 36 and 45 the remainder is always 7.

We should first find the LCM of 30, 36 and 45

We get that the LCM of the three numbers is 280 (working attached).

So now;

\frac{180}{30} = 6

\frac{180}{36} = 5

\frac{180}{45} = 4

But we need a number that leaves a remainder of 7 so we add 7 to 180 to get; 180 + 7 = 187.

5 0
3 years ago
Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL
scoray [572]

Answer:

8(x^2+y^2)-4x-30y+23=0

Step-by-step explanation:

<u />

<u>Distance formula</u>

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let P(x, y) = any point on the locus

Let A = (0, 2)    

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

PA=\dfrac{1}{3}PB

Therefore, using the distance formula:

\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}

Square both sides:

\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]

\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)

Multiply both sides by 9:

\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9

\implies 8x^2+8y^2-4x-30y+23=0

\implies 8(x^2+y^2)-4x-30y+23=0

3 0
2 years ago
PLZ HELP ASAP!!!!<br><br> Solve for X:<br> 2X^3 = 54
mariarad [96]
X=3

Divide both sides of the equation by 2
X^3 =27

Write the number in exponential form with an exponent of 3
X^3=3^3

Since the exponents are the same, set the bases equal
X=3
6 0
3 years ago
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