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Arte-miy333 [17]
2 years ago
11

A Ferris wheel has a radius of 80 feet. Two particular cars are located such that the central angle between them is 165º. To the

nearest tenth, what is the length of the intercepted arc between those two cars on the Ferris wheel?
Mathematics
1 answer:
Alex2 years ago
7 0

Answer: 230.4 feet

Step-by-step explanation:

arc length = circumfrance x fraction of a circle

                 = 2\pi r x \frac{165}{360}

                 = \frac{2*\pi *80*165  }{360}

                 = 230.4 feet to nearest tenth

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2. Draw the image of RST under the dilation with scale factor 2/3 and center of dilation (1,-1). Label the image RST .
professor190 [17]

Answer:

From the graph: we have the coordinates of RST i.e,

R = (2,1) , S = (2,-2) , T = (-1,-2)

Also, it is given the scale factor \frac{2}{3} and center of dilation C (1,-1)

The mapping rule for the center of dilation applied for the triangle as shown below:

(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)

or

(x, y) \rightarrow (\frac{2}{3}x -\frac{2}{3}+1 , \frac{2}{3}y+\frac{2}{3}-1)

or

(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )

Now,  

for R = (2,1)  

the image R' = (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(1)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )

⇒ R' = (\frac{5}{3} , \frac{1}{3})  

For S = (2, -2) ,

the image S'=  (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ S' = (\frac{5}{3} , -\frac{5}{3})

and For T = (-1, -2)

The image T' =  (\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ T' = (\frac{-1}{3} , \frac{-5}{3})

Now, label the image of RST on the graph as shown below in the attachment:

5 0
2 years ago
Use the Pythagorean Theorem to find the length of the leg in the triangle shown below.
Natali [406]
The answer to what the length of the leg would be is 15.

You would do this problem by first writing down your Pythagorean Theorem, which is a^2 + b^2 = c^2.

Since we have our hypotenuse which is c^2 in our equation, we would write or insert the number we have.

So our equation could be that a or b leg equals 20, it doesn’t matter which one.

So we could write, 20^2 + b^2 = 25^2. So we don’t know what b leg is.

First we should figure out what 20^2 is and what 25^2 is.

20^2 is 400 and 25^2 is 625.

Our equation now comes to 400 + b^2 = 625.

Now we take 400 and subtract it from
625 -> 400 + b^2 = 625
-400.

So 625 - 400 comes out to be 225.

Lastly instead of squaring or putting 225 to the second power, we do the opposite.

So instead of squaring 225 we must square root 225. √ 225 .

The square root of √ 225 comes out to be 15.

3 0
3 years ago
from a set of seven math books, nine science books, and five literature books, in how many ways can a student select two from ea
Over [174]
There are 7 math books, 9 science books and 5 literature books. Student has to select 2 books from each set.

This is a combination problem.

Number of ways to select 2 math books from 7 books = 7C2 = 21
Number of ways to select 2 science books from 9 books = 9C2 = 36
Number of ways to select 2 literature books from 5 books = 5C2 = 10

Total number of ways to select 2 books from each set = 21 x 36 x 10 = 7560 ways.

So there are 7560 ways to select 2 books from each set of seven math books, nine science books, and five literature books
6 0
3 years ago
Multiply 2 1/2 * 3/5 in simplest form show work
xz_007 [3.2K]

I can’t show work but the answer is 3/5

5 0
3 years ago
Read 2 more answers
Need help............
svp [43]

Answer:

i would say C

Step-by-step explanation:

6 0
2 years ago
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