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2 years ago

11

Whats is the answer too the equation 90000x604982?

1 answer:

defon2 years ago

4 0

90000x604982 = 54448380000

Alternative form: 5.444838 x 10^10

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Need help with my work pleasem

Galina-37 [17]

Let me start with the second screenshot :-
To find the scale factor you have to enlarge/ dilate A to get B you have a given side so assume that all sides are dilated to the same extent
: . $1 \frac{1}{2} / \frac{3}{4} = 2
$

Thus one can say m would be
$\frac{1}{2} * 2 = 1$

And N would be
$\frac{5}{6} * 2 = \frac{10}{6}$

7 0

3 years ago

Find the area of a plane figure bounded by lines

natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1

Now, integrate from x = -2 to x = 1

$\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,$ <em>the bottom of the integral is -2 </em>

= $\int\limits^1_2 {x+6-x^{2}-2x-4 } \,$

= $\int\limits^1_2 {-x^{2}-x+2 } \,$

= $\frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,$

= $(\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))$

= $(\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)$

= $\frac{-9}{3} + \frac{3}{2} +6$

= -3 + 1.5 + 6

= 4.5

3 0

3 years ago

Suppose y varies inversely with x, and y = 3 when x = 1/3. What is the inverse variation equation that relates x and y ?

Sav [38]

Good the answer is going to be 1/3x3y

8 0

3 years ago

Read 2 more answers

the area of a rectangle city park is 25/54 sqaure miles. the length of the park is 5/9 mile. what is the width in miles of the p

andreyandreev [35.5K]

A = lw

Plug in what we know:

25/54 = (5/9)w

Divide 5/9 to both sides or multiply by its reciprocal, 9/5:

25/54 * 9/5 = w

Multiply the numerators and denominators together:

225/270 = w

Simplify:

<span>w = 5/6</span>

6 0

3 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>

sladkih [1.3K]

Answer:

$\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2$

$\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta$

17) Given:

$\theta$ = 240°
r = 16 ft

$\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2$

19) Given:

$\theta=\dfrac{3 \pi}{2}$
r = 14 cm

$\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2$

21) Given:

$\theta=\dfrac{ \pi}{2}$
r = 10 mi

$\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2$

23) Given:

$\theta$ = 60°
r = 7 km

$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

3 0

2 years ago