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Rufina [12.5K]
2 years ago
13

Please help the problem is below.

Mathematics
1 answer:
Anna007 [38]2 years ago
6 0

Answer:

1. $1,122
2. $485.25

3. $440

4. $2,047.25

Step-by-step explanation:

1. 22 feet * 17 feet = 374 square feet * $3 per square foot = $1,122
2. 17 feet * 10 feet * 4 walls = 680 square feet. 680 feet - (7ft*3ft for the door) - (2*2ft*3ft for the windows) = 647 square feet * $0.75 per square foot = $485.25
3. 374 square feet/ $88 per gallon = 4.25 gallons which rounds up to 5 gallons, and 5 gallons at a cost of $88 per gallon = $440
4. $1,122 + $485.25 + $440 = $2,047.25

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Work out the circumference of this circle.
kirill [66]

Answer:

62.84

Step-by-step explanation:

pie=3.142

c=pie * diameter

r=10cm

d=2r

d=2(10)=20cm

c=3.142 * 20

c=62.84

4 0
3 years ago
Read 2 more answers
The diagonal length of a rectangular playing field is 76 feet, and its width is 48 feet. How long is the playing field?
Sauron [17]

The length of playing field is 58.9 feet

<u>Solution:</u>

Given that, the diagonal length of a rectangular playing field is 76 feet,  

And its width is 48 feet.  

<em><u>To find: length of playing field</u></em>

Now, we know that, <em>diagonal, width and length of a rectangle will form an right angle triangle with diagonal as hypotenuse. </em>

So, now, in a right angled triangle  we can use pythagorean theorem to find the length

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

By above definition, In a right angled triangle ABC we get

c^2 = a^2 + b^2

Where "c" is the length of hypotenuse

"a" is the length of one leg of right angled triangle

"b" is the length of other leg of right angled triangle

\begin{array}{l}{\text {Then, diagonal = width }^{2}+\text { length }^{2}} \\\\ {76^{2}=48^{2}+\text {length }^{2}} \\\\ {\text {Length }^{2}=76^{2}-48^{2}} \\\\ {\text {Length }^{2}=5776-2304}\end{array}

\begin{array}{l}{\text { Length }^{2}=3472} \\\\ {\text { Length }=\sqrt{3472}} \\\\ {\text { Length }=58.92}\end{array}

Hence, the length of the rectangular field is 58.9 feet

7 0
3 years ago
Need help with this im confused
Jet001 [13]

Answer:

-\frac34 -\frac14 i

Step-by-step explanation:

Let's start with distributing: \frac1{4i}-\frac{3i}{4i} Simplify i with i in the second term, and rearrange.-\frac34 +\frac1{4i}. Since i in the denominator looks ugly, let's multiply top and bottom by i. -\frac34 +\frac i{4i^2} = -\frac34 +\frac i{4(-1)} =-\frac34 -\frac14 i. The middle passage is based on the fact that, by definition, i^2=-1

6 0
3 years ago
a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

4 0
3 years ago
Ons: Practice
Sedaia [141]

Answer:

x = 18

Step-by-step explanation:

Given

\frac{x}{6} - 7 = -4

Required

Solve for x

\frac{x}{6} - 7 = -4

Add 7 to both sides

\frac{x}{6} - 7+7 = -4+7

\frac{x}{6}  = -4+7

\frac{x}{6}  = 3

Multiply through by 6

6 * \frac{x}{6}  = 3 * 6

x = 3 * 6

x = 18

7 0
3 years ago
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