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maxonik [38]
3 years ago
8

In order to practice at home, Tadeo purchased a basketball and a volleyball that cost a total of $67, not including tax. If the

price of the basketball b is $4 more than twice the cost of the volleyball v. Which system of linear equations could be used to determine the price of each ball?
a) b + v = 67; b = 2v - 4
b) b + v = 67; b = 2v + 4
c) b + v = 4; b = 2v - 67
d) b + v = 4; b = 2v + 67
Mathematics
2 answers:
Aleks [24]3 years ago
7 0
The answer would be B) b+v=67; b=2v+4
hoa [83]3 years ago
6 0

Answer: B. b + v = 67; b = 2v + 4

Step-by-step explanation: since both the basketball and the volleyball cost 67, we can represent that as b + v = 67.

If you multiplied the cost of the volleyball by 2 and then added 4, you would get the cost of the basketball:

b = 2v + 4

Hope this was helpful! Let me know if you have any further questions. :)

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