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lutik1710 [3]
2 years ago
15

Can you create a rectangular prism net with a surface area of 394in

Mathematics
1 answer:
Alina [70]2 years ago
5 0

Answer

now i'm going to say i'm not 100% sure but i think its 168

Step-by-step explanation:

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The total profit from the Spanish club fund-raiser varies directly with the number of dinner tickets sold. If the sale of 22 tic
worty [1.4K]

Answer:

61 tickets

Step-by-step explanation:

It is given that,

The total profit from the Spanish club fund-raiser varies directly with the number of dinner tickets sold.

If the sale of 22 tickets results in a profit of $253.

Profit in 1 ticket = \dfrac{253}{22}=\$11.5

Let x tickets are sold in order to reach the fund-raising goal of $700.

x=\dfrac{22}{253}\cdot700\\\\=\$60.86

or

= 61 tickets

Hence, 61 tickets must be sold to reach the fund-raising goal of $700.

6 0
3 years ago
A factory makes an oil mixture by mixing oils of grades A and B as follows. For every 2.3 liters of grade A oil, 1.2 liters of g
lozanna [386]
<span>To produce 1000L of mixture the factory will need 657 liters of grade A and 343 liters of grade B. To determine this you have to figure out the percentage of each grade in the mixture. The ratio is 2.3 liters to 1.2 liters. Therefor in this scenario the unit equaling 100% is 3.5 liters. To find the percentage of grade A you divide the amount used by the total amount of the unit 100%: 2.3 divided by 3.5 = .657 (multiply the answer by 100 to get 65.7%). To find the percentage of grade B you divide the amount used by the total amount of the unit 100%: 1.2 divided by 3.5 = .343 (multiply the answer by 100 to get 34.3%) To test your answer make sure both percentages add up to 100%: 65.75 plus 34.35 = 100% To determine how much of grade A and grade B is needed for a set amount of liters you multiply the percentage by the liters needed. For this situation you multiply 65.7% (when multiplying percentages you need to multiply in decimal form). For grade A you multiply .657 (65.7%) by 1000 liters = 657 liters For grade B you multiply .343 (34.3%) by 1000 liters = 343 liters To test your answer you can use the same addition as you did to test the percentages: 657 liters plus 343 liters = 1000 liters</span>
4 0
3 years ago
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There are fewer than 8 gallons of gas in the tank how do I write an inequality for that
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G<8 g as a variable for gallons
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3 years ago
The mean amount purchased by a typical customer at Churchill's Grocery Store is $27.50 with a standard deviation of $7.00. Assum
Schach [20]

Answer:

a) 0.0016 = 0.16% probability that the sample mean is at least $30.00.

b) 0.8794 = 87.94% probability that the sample mean is greater than $26.50 but less than $30.00

c) 90% of sample means will occur between $26.1 and $28.9.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 27.50, \sigma = 7, n = 68, s = \frac{7}{\sqrt{68}} = 0.85

a. What is the likelihood the sample mean is at least $30.00?

This is 1 subtracted by the pvalue of Z when X = 30. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem, we have that:

Z = \frac{X - \mu}{s}

Z = \frac{30 - 27.5}{0.85}

Z = 2.94

Z = 2.94 has a pvalue of 0.9984

1 - 0.9984 = 0.0016

0.0016 = 0.16% probability that the sample mean is at least $30.00.

b. What is the likelihood the sample mean is greater than $26.50 but less than $30.00?

This is the pvalue of Z when X = 30 subtracted by the pvalue of Z when X = 26.50. So

From a, when X = 30, Z has a pvalue of 0.9984

When X = 26.5

Z = \frac{X - \mu}{s}

Z = \frac{26.5 - 27.5}{0.85}

Z = -1.18

Z = -1.18 has a pvalue of 0.1190

0.9984 - 0.1190 = 0.8794

0.8794 = 87.94% probability that the sample mean is greater than $26.50 but less than $30.00.

c. Within what limits will 90 percent of the sample means occur?

Between the 50 - (90/2) = 5th percentile and the 50 + (90/2) = 95th percentile, that is, Z between -1.645 and Z = 1.645

Lower bound:

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 27.5}{0.85}

X - 27.5 = -1.645*0.85

X = 26.1

Upper Bound:

Z = \frac{X - \mu}{s}

1.645 = \frac{X - 27.5}{0.85}

X - 27.5 = 1.645*0.85

X = 28.9

90% of sample means will occur between $26.1 and $28.9.

4 0
3 years ago
A snack bar sells two sizes of snack packs. A large snack pack costs 5 dollars. A small snack pack costs 3 dollars. In one day t
il63 [147K]
X=cost of large snack Y=cost of small snack X+Y=60 5X+3Y=220 To solve for y, solve x+y=60 for x. Subtract y from both sides so you're left with x=-y+60. You now plug in -y+60 for x in the second equation. 5(-y+60)+3y=220 -5y+300+3y=220 -2y+300=220 -2y=-80 Y=40 40 small snack packs is the final answer
7 0
3 years ago
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