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prisoha [69]
3 years ago
8

The directions on a seed packet say to plant the seeds 178 inches apart. What is the decimal equivalent of this mixed number?

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

1.875 inches apart

Step-by-step explanation:

I think you meant "1  7/8 inches."  

Convert 7/8 to a decimal fraction.  Divide 7 by 8 on a calculator; you will get 0.875.  Then:   1  7/8 inches = 1.875 inches.  

Plant the seeds 1.875 inches apart.

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4/7+3/7 1/5.3/2-4/10
Westkost [7]

Answer:

3/10

Step-by-step explanation:

=4/7 + 9/70 - 4/10

=l.C.M of 7 , 70 and 10 =70

=4/7 .10/10 +9/70 -4/10 .7/7

=40/70 +9/70 -28/70

=40+9-28/70

=49-28/70

=21/70

=3/10

7 0
1 year ago
What is 2.602 as a mixed number
MrRa [10]
I think that it is 2 602/1000
6 0
3 years ago
Can someone help with this?! The answer choices are 1, 1.3, 1.45, and 1.9!
Zarrin [17]
The answer is 1.45 ......
7 0
3 years ago
Read 2 more answers
Which system of linear equations appears to have a solution of (–1, 4)? On a coordinate plane, 2 lines intersect at (1, negative
madam [21]

Answer:

On  coordinate plane, 2 lines intersect at (negative 1, 4)

Step-by-step explanation:

negative 1 = -1, 4 = 4

therefore this means that this coordinate is also (-1, 4)

6 0
3 years ago
Read 2 more answers
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
2 years ago
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