The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
0 ≤y ≤ 60
Step-by-step explanation:
The range is values the y can take
y goes from 0 to 60
10 ≤y ≤ 60
Step-by-step explanation:
Given
f(x) = 8x - 9
Then
For a.
f(3y - 1 ) = 8(3y - 1 ) - 9
= 24y - 8 - 9
= 24y - 17
Now for b.
f(x) = - 23
or, 8x - 9 = - 23
8x = - 23 + 9
8x = - 14
x = - 14 / 8
x = - 7 / 4
Hope it will help :)
Answer:
Piper's claim is not correct.
Step-by-step explanation:
3(2(-3)+2) = 5(-3)+6
3(-6+2) = -15 + 16
-18 + 6 = 1
-12 = 1
Ahh, basic shapes. Split up the weird shapes into easier ones. #1 can be truned into 2 trapezoids. #2 can be turned into 2 circles. #3 is a triangle and a trapezoid. #4 is 2 right triangles. #5 is a rectangel and a traingle. Finally, #6 is 3 traigles and a rectangle. Do you see how we broke the hard shapes into easier shapes?
