I believe
the answer is C. 0.14cm.
The zero error in vernier caliper is read by the distance by which the zero of the movable part of the scale is shifted from the zero of the cm ruler in the tool, which is the unmovable part of the tool. The movable part has a scale accuracy of 0.1 cm, while the other has a scale accuracy of 1 cm. And we always use the lowest scale, which is here the 0.1 scale which has greater accuracy with 10 times the 1 cm ruler, to find our errors.
Hope this helps!
Answer:
Explanation:
y = Distance from the center point
d = Separation between slits = 0.3 mm
D = Distance between slit and screen = 1.5 m
= Wavelength = 700 nm
m = Order = 1
We have the relation
The distance from the screen at which the first bright fringe beyond the center fringe appear is .
The answer is A) because knowing Net force is equal too mass * acceleration, we can sub in what is given, the net force here would be 5N so the equation the looks like 5N=10kg*a and then dividing out 10kg we are then left with .5 m/s^2
Answer:
what if I do and b then someone else c I don't have enough time pls