Answer:
The magnitude of the force on the charged particle is 1.3125nN
Explanation:
Given;
magnitude of charge, q = +7.5 nC
velocity of the charged particle, v = 25 m/s
strength of magnetic field, B = 7 mT
Magnitude of force on charged particle in magnetic field is given as;
F = qvB
where;
F is the force on the moving particle
q is the charged particle
B is magnetic field strength
Substitute in the given values in the above equation, we will have;
F = 7.5 x 10⁻⁹ x 25 x 7 x 10⁻³
F = 1.3125 x 10⁻⁹ N
F = 1.3125nN
Therefore, the magnitude of the force on the charged particle is 1.3125nN