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sergeinik [125]
3 years ago
14

What connects the upper motor neurons to lower motor neurons?

Physics
1 answer:
skad [1K]3 years ago
7 0

Answer:

The upper motor neurons synapse in the spinal cord connect with anterior horn cells of lower motor neurons, usually via interneurons. The anterior horn cells are the cell bodies of the lower motor neurons and are located in the grey matter of the spinal cord.

Explanation:

Interneurons are the central nodes of neural circuits, enabling communication between the upper motor neurons, sensory or motor neurons located in the brain and spinal cord and they send signals to lower motor neurons or central nervous system (CNS) in the brain stem and spinal cord . When they get a signal from the upper motor neurons, they send another signal to your muscles to make them contract. They play vital roles in reflexes, neuronal oscillations, and neurogenesis in the adult mammalian brain.

Renshaw cells are among the very first identified interneurons. They are excited by the axon collaterals of the motor neurons. In addition, Renshaw cells make inhibitory connections to several groups of motor neurons.

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Bogdan [553]

Answer and Explanation:

They are both correct.

This is because potential energy is when there is potential for the object to have energy, while kinetic energy is energy that is moving already.

So, as the ball falls, it loses its potential energy, or "still/Stalled" energy, and gains kinetic energy, or moving energy.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

7 0
3 years ago
Solve these problems on charges by finding out Q1 and Q2. Q1Q2= 4x10^6, Q1 + Q2 =8.00×10^-6​
inna [77]

Answer:

Answer:

Q_1 = 7Q

1

=7

Q_2 = 10Q

2

=10

Q_3 = 13.5Q

3

=13.5

Step-by-step explanation:

Given

5, 7, 7, 8, 10, 11, 12, 15, 17.

Required

Determine Q1, Q2 and Q3

The number of data is 9

Calculating Q1:

Q1 is calculated as:

Q_1 = \frac{1}{4}(N + 1)Q

1

=

4

1

(N+1)

Substitute 9 for N

Q_1 = \frac{1}{4}(9 + 1)Q

1

=

4

1

(9+1)

Q_1 = \frac{1}{4}*10Q

1

=

4

1

∗10

Q_1 = 2.5th\ itemQ

1

=2.5th item

This means that the Q1 is the mean of the 2nd and 3rd data.

So:

Q_1 = \frac{1}{2}(7+7)Q

1

=

2

1

(7+7)

Q_1 = \frac{1}{2}*14Q

1

=

2

1

∗14

Q_1 = 7Q

1

=7

Calculating Q2:

Q2 is calculated as:

Q_2 = \frac{1}{2}(N + 1)Q

2

=

2

1

(N+1)

Substitute 9 for N

Q_2 = \frac{1}{2}(9 + 1)Q

2

=

2

1

(9+1)

Q_2 = \frac{1}{2}*10Q

2

=

2

1

∗10

Q_2 = 5th\ itemQ

2

=5th item

Q_2 = 10Q

2

=10

Calculating Q3:

Q3 is calculated as:

Q_3 = \frac{3}{4}(N + 1)Q

3

=

4

3

(N+1)

Substitute 9 for N

Q_3 = \frac{3}{4}(9 + 1)Q

3

=

4

3

(9+1)

Q_3 = \frac{3}{4}*10Q

3

=

4

3

∗10

Q_3 = 7.5th\ itemQ

3

=7.5th item

This means that the Q3 is the mean of the 7th and 8th data.

So:

Q_3 = \frac{1}{2}(12+15)Q

3

=

2

1

(12+15)

Q_3 = \frac{1}{2}*27Q

3

=

2

1

∗27

Q_3 = 13.5Q

3

=13.5

4 0
3 years ago
Uranus has more than 14 times as much mass as earth, yet the gravitational force is less. how can that be?
Anarel [89]
It has more mass, yes. But it has less of a gravitational pull because it is farther away from the sun than the Earth is
3 0
4 years ago
Read 2 more answers
Consider an electron and a proton separated by a distance of 4.5 nm. (a) what is the magnitude of the gravitational force betwee
Dmitry_Shevchenko [17]
A.) For letter a, we use the law of universal gravitation using the constant G = 6.674×10−<span>11 m3</span>⋅kg−1⋅s−<span>2

Grav. F = G*m1*m2*(1/d^2)

m1 is mass of electron = </span>9.11 × 10-31<span> kg
m2 is mass of proton = </span>1.67 × 10<span>-27 kg
d = 4.5 nm = 4.5 x 10^-9 m

Grav F = 5.01 x 10^-51 N

b.) </span>For letter b, we use the Coulomb's using the constant k = 9×10^9 N

Electric force = k*Q1*Q2*(1/d^2)
Q1 is charge of electron = -1.6 × 10-19 C
Q2 is charge of proton = +1.6 × 10-19 C

Electric force = 1.14 x 10^-11 N
6 0
3 years ago
Please help, have no idea on how to solve it. Joel is pulling a sled up a hill at an angle of 30 degrees above the horizontal fo
lubasha [3.4K]

Answer:

-1m

Explanation:

I'm assuming it means that you treat the distance travelled as a displacement vector (distance of a particular direction and magnitude)

If he turns 180 degrees, he is travelling in the exact opposite direction to his original direction of travel. Therefore if he was travelling 5m in one direction, then afer his turn he travels 6m in the exact opposite direction. Opposite directions can be interpreted as the negative of the original direction.

Resultant vectors are the sum of vectors.

The sum of vectors is equal to 5m + - 6m = -1m

6 0
3 years ago
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