I’m not sure but I think it’s 
△ m=5 and △= -3 and so 
Answer: 5/△-3 m/s 
So sorry if it’s wrong
        
             
        
        
        
Compression is above the equilibrium and rarefaction is below
        
             
        
        
        
The de Broglie wavelength of a 0.56 kg ball moving with a constant velocity of 26 m/s is 4.55×10⁻³⁵ m.
<h3>De Broglie wavelength:</h3>
The wavelength that is incorporated with the moving object and it has the relation with the momentum of that object and mass of that object. It is inversely proportional to the momentum of that moving object.
λ=h/p
Where, λ is the de Broglie wavelength, h is the Plank constant, p is the momentum of the moving object.
Whereas, p=mv, m is the mass of the object and v is the velocity of the moving object.
Therefore, λ=h/(mv)
λ=(6.63×10⁻³⁴)/(0.56×26)
λ=4.55×10⁻³⁵ m.
The de Broglie wavelength associated with the object weight 0.56 kg moving with the velocity of 26 m/s is λ=4.55×10⁻³⁵ m.
Learn more about de Broglie wavelength on
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Answer:
O a force that opposes motion
 
        
             
        
        
        
Answer:
Fundamental frequency in the string will be 25 Hz
Explanation: 
We have given length of the string L = 1.2 m
Speed of the wave on the string v = 60 m/sec
We have to find the fundamental frequency
Fundamental frequency in the string is equal to  , here v is velocity on the string and L is the length of the string
, here v is velocity on the string and L is the length of the string 
So frequency will be equal to 
So fundamental frequency will be 25 Hz