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vaieri [72.5K]
3 years ago
8

Which of the following situations could cause light to diffract?

Physics
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

B. Light passes through a small opening

Explanation:

Diffraction is one of the properties of wave defined as the bending of wave around corners. It occurs mostly when waves passes through a tiny opening or slit. The type of waveform generated by the wave depends on the type of opening or slit that the medium passes through. The opening can be tiny or large.

Based on the definition, it can be inferred that the situation that causes light waves to diffract is when the light passes through a small opening. For example, the light of a torch passing through a tiny door hole is diffraction.

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The rubber band contains .......potential energy as it is stretched.
kodGreya [7K]

Answer:

elastic potential energy

You input potential (stored) energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this kind of potential energy is specifically called elastic potential energy.

Explanation:

4 0
1 year ago
What is the average velocity of a car that travels 50 kilometers due west in 0.50 hour?
Pie

Average Velocity= displacement/time   Av=50/0.50   Av=100

4 0
3 years ago
Suppose the initial kinetic energy and final potential energy in an experiment are both zero. What can you conclude?
puteri [66]

Answer:

That an item is neither moving nor staying still in a position that is building up energy.

Explanation:

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3 years ago
Read 2 more answers
Suppose that the sound level of a conversation is initially at an angry 70 db and then drops to a soothing 50 db. assuming that
stepan [7]
Angry sound level = 70 db
Soothing sound level = 50 db
Frequency, f = 500 Hz
Assuming speed of sound = 345 m/s
Density (assumed) = 1.21 kg/m^3
Reference sound intensity, Io = 1*10^-12 w/m^2

Part (a): Initial sound intensity (angry sound)
10log (I/Io) = Sound level
Therefore,
For Ia = 70 db
Ia/(1*10^-12) = 10^(70/10)
Ia = 10^(70/10)*10^-12 = 1*10^-5 W/m^2

Part (b): Final sound intensity (soothing sound)
Is = 50 db
Therefore,
Is = 10^(50/10)*10^-12 = 18*10^-7 W/m^2

Part (c): Initial sound wave amplitude
Now,
I (W/m^2) = 0.5*A^2*density*velocity*4*π^2*frequency^2

Making A the subject;
A = Sqrt [I/(0.5*density*velocity*4π^2*frequency^2)]

Substituting;
A_initial = Sqrt [(1*10^-5)/(0.5*1.21*345*4π^2*500^2)] = 6.97*10^-8 m = 69.7 nm

Part (d): Final sound wave amplitude
A_final = Sqrt [(1*10^-7)/(0.5*1.21*345*4π^2*500^2)] = 6.97*10^-9 m = 6.97 nm
4 0
3 years ago
José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be remo
satela [25.4K]

Answer:

179 kg

Explanation:

8 0
3 years ago
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