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4 years ago

Which of the following situations could cause light to diffract?

Physics

1 answer:

adelina 88 [10]4 years ago

7 0

Answer:

B. Light passes through a small opening

Explanation:

Diffraction is one of the properties of wave defined as the bending of wave around corners. It occurs mostly when waves passes through a tiny opening or slit. The type of waveform generated by the wave depends on the type of opening or slit that the medium passes through. The opening can be tiny or large.

Based on the definition, it can be inferred that the situation that causes light waves to diffract is when the light passes through a small opening. For example, the light of a torch passing through a tiny door hole is diffraction.

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A 50N girl pushes a 10,000 N car with force of 200N. What is the force the car pushes back at the girl? *

miss Akunina [59]

Answer:

200N

Explanation:

EVERY FORCE IS OPPOSED BY AN EQUAL FORCE, REGARDLESS OF THE WEIGHT OF THE OBJECTS APPLYING THE FORCE.

8 0

3 years ago

Is water a mixture or substance

elena55 [62]

Hey!

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Answer:

Substance

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Explanation:

Water is a substance created with oxygen and hydrogen.

A mixture is when more than one substance are mixed together.

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Hope This Helped! Good Luck!

7 0

3 years ago

Read 2 more answers

A motorist is driving at 20m/s when she sees that a traffic light 200m ahead has just turned red. She knows that this light stay

yuradex [85]

Answer:

5.71428571422 m/s

Explanation:

u = Initial velocity = 20 m/s

v = Final velocity

s = Displacement

a = Acceleration

Time taken = 15-1 = 14 s

Distance traveled in 1 second = $20\times 1=20\ m$

$s=ut+\frac{1}{2}at^2\\\Rightarrow 200-20=20\times 14+\frac{1}{2}\times a\times 14^2\\\Rightarrow a=\frac{2(180-20\times14)}{14^2}\\\Rightarrow a=-1.02040816327\ m/s^2$

$v=u+at\\\Rightarrow v=20-1.02040816327\times 14\\\Rightarrow v=5.71428571422\ m/s$

The speed as she reaches the light at the instant it turns green is 5.71428571422 m/s

4 0

4 years ago

PLEASE HELP IF U PASS TESTS

bezimeni [28]

I think iron? i’m not 100% sure

5 0

3 years ago

Read 2 more answers

A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can

Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

$\mu mg = m\frac{v^2}{r}$

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

$\mu$ is the coefficient of friction between the tires and the road