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djyliett [7]
2 years ago
9

An experiment requires the population of the bacteria to reach 2 million before the experiment can begin. The reproduction rate

of the bacteria can be modeled by the exponential equation Y= 8 times 7^x. About how many hours X will it take for the bacteria population to reach 2 million?
round your answer the the nearest hour
Mathematics
1 answer:
Furkat [3]2 years ago
6 0

Answer:

about 6 hours

Step-by-step explanation:

8( {7}^{x} ) = 2( {10}^{6} )

{7}^{x}  = 250000

x =  \frac{ ln(250000) }{ ln(7) }  = 6.39

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Item 15 Your math class is collecting canned food for a local food drive. The goal is to collect at least 130 cans but no more t
Margarita [4]

For this case, the first thing we must do is define variables.

We have then:

n: number of cans that each student must bring

We know that:

The teacher will bring 5 cans

There are 20 students in the class

At least 105 cans must be brought, but no more than 205 cans

Therefore the inequation of the problem is given by:

Answer:

105 <u><</u> 20n + 5 <u><</u> 205

the possible numbers n of cans that each student should bring in is:

105 <u><</u> 20n + 5 <u><</u> 205

8 0
3 years ago
Only answer this if you have an explanation and if you know what the answer is.
laiz [17]

Answer:

34

Step-by-step explanation:

5 1/10=5.1=5.10

5.10÷0.15

=510÷15

=34

3 0
3 years ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Use the commutative and associative properties of multiplication to write an expression equivalent to (4⋅5)⋅3.
Darina [25.2K]
Commutaive property says
ab=ba or expanded to say
abc=cba

associative peropty =
a(bc)=(ab)c

so using that
first mix them up knowing that we can move the parenthaseese
all possible equivelnt ones are
4*(5*3)
(3*5)*4
3*(5*4)
(3*4)*5
3*(4*5)
 
4 0
3 years ago
1/4 times X -1+ 3X equals 2
iris [78.8K]

Answer:

41

Step-by-step explanation:

4 0
3 years ago
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