Answer:
Compound interest = Rs 1,575 (Approx.)
Step-by-step explanation:
Given:
Amount invested = R.s 6,500
Rate of interest = 7.5% per annum
Number of year = 3 year
Find:
Amount of compound interest
Computation:
Compound interest = P[(1+r)ⁿ - 1]
Compound interest = 6500[(1+7.5%)³ - 1]
Compound interest = 6500[(1+0.075)³ - 1]
Compound interest = 6500[(1.075)³ - 1]
Compound interest = 6500[1.2423 - 1]
Compound interest = 6500[0.2423]
Compound interest = 1574.95
Compound interest = Rs 1,575 (Approx.)
Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
Answer:
a= d-r +c
Step-by-step explanation:
a-c = d-r
+c
a= d-r +c
Answer: 600
Step-by-step explanation:
I just took the test
Answer:
11:05
Step-by-step explanation:
