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iogann1982 [59]
2 years ago
7

What is the value of sin(80°)cos(20°) – cos(80°)sin(20°)?

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
6 0

The value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

<h3>What is difference formula in trignometry?</h3>

The difference formula in trignometry for the sine funciton is given as,

\sin(A-B)=\sin(A)\cos(B) -\cos(A)\sin(B)

The trignometric equation given in the problem is,

\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)

Compare this equation with the above eqution, we get,

A=80^o\\B=20^o

Thus, this equation can be written as,

\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(80-20)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(60)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\dfrac{\sqrt{3}}{2}

Hence, the value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

Learn more about the difference formula in trignometry here;

brainly.com/question/2142049

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