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Liula [17]
3 years ago
8

The foot of a ladder is placed 10 feet from a wall. If the top of the ladder rests 13 feet up on the wall, find the length of th

e ladder.
Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
10 squared + 13 squared = your answer squared.
So do that then take the square root of whatever you get.
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Solve for W.<br><br> 4w-4+2(5w+8)=-2(w+3)<br><br> Simplify your answer as much as possible.
gayaneshka [121]

Answer:

w = -\frac{9}{8}

Step-by-step explanation:

The question is  4w-4+2(5w+8)=-2(w+3)

We can first use distributive property to simplify, the distributive property is  a(b+c)=ab+ac

Thus we have:

4w-4+2(5w+8)=-2(w+3)\\4w-4+10w+16=-2w-6

<em>Now we combine like terms and simplify to get the final answer for w</em><em>.</em>

4w-4+10w+16=-2w-6\\14w+12=-2w-6\\14w+2w=-6-12\\16w=-18\\w=\frac{-18}{16}\\w=-\frac{9}{8}

Thus, w = -\frac{9}{8}

8 0
3 years ago
Read 2 more answers
If a bag contains 10 red,6 yellow,24 blue,and 8 white balloons , what part-to-whole ratio of blue balloons to all balloons
Anna11 [10]

Answer:

A. 1:2.

Step-by-step explanation:

24: 10+6+8+24

24:48

\frac{24}{24} = 1

\frac{48}{24} = 2

1:2

5 0
3 years ago
A square with side x, is changing with time where x(t)=3t+1. What is the formula for the rate of change of the area of the squar
lawyer [7]

Answer:

  A' = 6(3t +1)

Step-by-step explanation:

The area is the square of the side length, so ...

  A = (3t +1)²

The derivative with respect to t is then

  A' = 2(3t +1)·(3) = 6(3t +1)

If you like, you can multiply out the area expression first, then differentiate.

  A = 9t² +6t +1

  A' = 18t +6

This can be factored, if you like, to ...

  A' = 6(3t +1)

5 0
3 years ago
In which situation is the distance traveled proportional to time? A: An airplane landing
Softa [21]

Answer:

Step-by-step explanation:

you add it my g

8 0
3 years ago
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What is the solution to the system of equations?
Natalka [10]

Answer:

x = 1    y = 3    z = 1

Step-by-step explanation:

(1)  x - 3y - z = -9           (2)   -2x + y + 2z = 3        (3)   2x + y + 3z = 8

                                2x(1)     <u>2x - 6y - 2z = -18</u>      (2)  <u>-2x + y + 2z = 3</u>

                                                 - 5y = -15                           2y + 5z = 11

                                                      y = 3                            2(3) + 5z = 11

                                                                                            6 + 5z = 11

                                                                                                  5z = 5

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       x - 3(3) - 1 = -9

       x - 9 - 1 = -9

            x - 10 = -9

            x = 1

Note:  If you write your equations across your paper, then the work can just flow down the paper.  It makes it so much easier to show the work you have done.  OK?

5 0
2 years ago
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