Divide it into chunks of area you can find. One way to divide it is
.. a rectangle 2 mi x 5 mi at upper left.
.. a rectangle 8 mi x 6 mi down the middle
.. a rectangle 3 mi x 4 mi at lower right
.. a triangle 5 mi x 6 mi at lower left
Then the sum of areas is
.. (2 mi)*(5 mi) +(8 mi)*(6 mi) +(3 mi)*(4 mi) + (1/2)*(5 mi)*(6 mi)
.. = 10 mi^2 +48 mi^2 +12 mi^2 +15 mi^2
.. = 85 mi^2
Answer:
cos 30
Step-by-step explanation:
cos 30 + sin 60 / 1+ sin 30 + cos 60
= root3 / 2 + root3/2 / 1 + 1/2 + 1/2
= root 6/2 by 4/2
= root 6/4
= root 3/2
= cos 30
Answer:
x= 60 y=50
Step-by-step explanation:
First to find x, all the degrees in a triangle add up to 180 degrees. So 50+70+x=180 which is also 120+x=180 which means x=60. Y is the exterior angle of x and a missing angle. Let's substitute the missing angle with the variable z. 60+50+z=180 which is 110+z=180 which means z is 70. So 180-x+z=y. 180-60+70=y which means y is equal to 50. Hope this helps!
Answer:
add up all the sides and angles then divide by the radius to get the square centimeters and it will lead to the surface area which is 14
Step-by-step explanation:
I had to calculate to double check
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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