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Effectus [21]
2 years ago
10

Jade farm has 9 chickens,each of which laid 3 eggs. Jases farm has 4 horses. ednas farm has chickens which laid a total of 23 eg

gs. jase wonders whose chickens laid more eggs.
Mathematics
2 answers:
Tomtit [17]2 years ago
6 0

The answer is that Jade's chickens laid more eggs. Since Jade's farm includes 9 chickens, which each laid 3 eggs, multiply 9 and 3 and you get 27. Edna's farm has chickens which, in total, laid 23 eggs, leading to Jade's chickens with 27 eggs to be more than the eggs laid by Edna's chickens. :)

UkoKoshka [18]2 years ago
5 0

Answer:

Jade's chickens laid more eggs.

Step-by-step explanation:

Jade farm has number of chickens = 9

Each chickens laid number of eggs = 3

Total number of eggs on Jade's farm = 9 × 3 = 27 eggs

Ednas farm has chickens which laid a total of 23 eggs.

Difference between number of  eggs = 27 - 23 = 4

Therefore, Jade's chickens laid 4 more eggs.

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Answer:

a = 60

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c = 150

Step-by-step explanation:

Numerele a, b și c sunt direct proporționale cu 2, 3 și 5.

Unde k este constantă de proporționalitate

a ∝ 2

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b = 3k

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c = 5k

Dacă media aritmetică a celor trei numere este egală cu 100, determinați numerele a, b și c

= 2k + 3k + 5k / 3 = 100

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Cross Multiply

= 10k = 3 × 100

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Împărțiți ambele părți la 10

k = 300/10

k = 30

Pentru numărul a

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