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Ahat [919]
2 years ago
5

The definition of the acceleration states that an object accelerates when it PLEASE HELP!!!

Chemistry
2 answers:
velikii [3]2 years ago
6 0

Maybe this can help.

In mechanics, speed increase is the pace of progress of the speed of an article regarding time (acceleration). Speed increases are vector amounts (in that they have greatness and direction). The direction of an item's speed increase is given by the direction of the net power following up on that article. The size of an item's speed increase, as depicted by Newton's Second Law, is the consolidated impact of two causes:

the net equilibrium of all outer powers acting onto that item — size is straightforwardly relative to this net coming about force;

that article's mass, contingent upon the materials out of which it is made — extent is conversely relative to the item's mass.

Rzqust [24]2 years ago
5 0

<u>There are two ways of thinking about it</u>:

  • First way: The definition of the acceleration states that an object accelerates when it <u>has a force applied to it</u>
  • Second way: The definition of the acceleration states that an object accelerates when it <u>changes its velocity</u>

<u></u>

<u><em>Reasons</em></u>

  • <u><em>For the first way</em></u><em>, by newton's second law, force equals to the product of mass times acceleration. The mass of the objects stays constant thus it is a constant in this equation. Thus when the Force isn't zero or bascially when it is applied, then the object must accelerate</em>
  • <u><em>For the second way</em></u><em>, acceleration is the rate of change of velocity, thus as velocity changes, the object must be accelerating</em>

<em />

Hope that helps!

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Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H1
nadya68 [22]

Answer:

\boxed{\text{B.}}

Explanation:

B.

\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O

NOT BALANCED. 7C on left and 6C on right.

C.

\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O

NOT BALANCED. 16H on left and 10H on right.

D.

\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O

NOT BALANCED. 7C on left and 14C on right.

3 0
3 years ago
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Luden [163]
Molecule
The smallest unit in a compound is its molecule.
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What kind of bond holds together atoms within a molecule?
sesenic [268]
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Which indicator most likely suggests that a chemical change is taking place? 1)change in size 2)change of color 3)change of stat
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8 0
3 years ago
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Consider the following reaction:
iren [92.7K]

Answer:

A. ΔG° = 132.5 kJ

B. ΔG° = 13.69 kJ

C. ΔG° = -58.59 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

We can calculate the standard enthalpy of the reaction (ΔH°) using the following expression.

ΔH° = ∑np . ΔH°f(p) - ∑nr . ΔH°f(r)

where,

n: moles

ΔH°f: standard enthalpy of formation

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g)) - 1 mol × ΔH°f(CaCO₃(s))

ΔH° = 1 mol × (-635.1 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1206.9 kJ/mol)

ΔH° = 178.3 kJ

We can calculate the standard entropy of the reaction (ΔS°) using the following expression.

ΔS° = ∑np . S°p - ∑nr . S°r

where,

S: standard entropy

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g)) - 1 mol × S°(CaCO₃(s))

ΔS° = 1 mol × (39.75 J/K.mol) + 1 mol × (213.74 J/K.mol) - 1 mol × (92.9 J/K.mol)

ΔS° = 160.6 J/K. = 0.1606 kJ/K.

We can calculate the standard Gibbs free energy of the reaction (ΔG°) using the following expression.

ΔG° = ΔH° - T.ΔS°

where,

T: absolute temperature

<h3>A. 285 K</h3>

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 285K × 0.1606 kJ/K = 132.5 kJ

<h3>B. 1025 K</h3>

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 1025K × 0.1606 kJ/K = 13.69 kJ

<h3>C. 1475 K</h3>

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 1475K × 0.1606 kJ/K = -58.59 kJ

5 0
3 years ago
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