Question

a diver dives from a 10m springboard. the equation f(t)=-4.9t^(2)+4t+10 models her height above the pool in seconds. what is her height at 1.5 second after diving off the springboard

Answer 1

Answer:

4.975 meters

Step-by-step explanation:

$f(1.5)= -4.9(1.5)^2+4(1.5) + 10\\\\f(1.5) = -4.9(2.25) + 6 + 10\\\\f(1.5) = -11.025 + 6 + 10\\\\f(1.5) = -11.025 + 16 \\\\f(1.5) = 4.975$

4.975 meters

-Chetan K