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Anna71 [15]
2 years ago
15

What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M

Chemistry
1 answer:
professor190 [17]2 years ago
8 0

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

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A 298 lb person must receive Heparin, determine the number of units given every hour (Heparin 8.0 units/kg per hour). Enter your
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Answer:

1,081.1 units of heparin should be given to 298 lb person.

Explanation:

We are given:

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8.0 units/kg\times 135.143 kg=1,081.144 units\approx 1,081.1 units

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4 0
2 years ago
A scientist made careful measurements of the pressure and temperature of many different gases. Based on these measurements, he c
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Answer:

c. law

Explanation:

Law -

It is type of statement , which helps to explain certain observations , in the form of mathematical relationship or verbal statements , is referred as a law .

Law is a widely accepted information , which can get altered by some new inventions or exception.

A law is stated in words as well as in the form of some mathematical relationships or equations.

Hence , from the given information of the question,

The correct option is c. law .

4 0
3 years ago
Which describes the molecule below?
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Answer:

Option D. A liquid with three unsaturated fatty acids.

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4 0
3 years ago
Consider Nal → Na+ + - and the following information.
Jobisdone [24]

Answer:

47 kJ·mol⁻¹  

Explanation:

NaI(s) ⟶ Na⁺(aq) + I⁻(aq); ΔH = ?

We can carry out this process in a series of steps.

1. Convert the solid to its gaseous ions.

NaI(s) ⟶ Na⁺(g) + I⁻(g); -ΔH(lat) = 704 kJ

2. Hydrate the Na⁺ ions

Na⁺(g) ⟶ Na⁺(aq); ΔH(hyd) = - 410.0 kJ

3. Hydrate the I⁻ ions

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4. Add the equations

Cancel ions that occur on opposite sides of the reaction arrow

                                      <u>ΔH/kJ·mol⁻¹</u>

NaI(s) ⟶ Na⁺(g) + I⁻(g);      +704

Na⁺(g) ⟶ Na⁺(aq);              - 410.0

I⁻(g) ⟶ I⁻(aq);                      -247

<u>NaI(s) ⟶ Na⁺(g) + I⁻(g)</u>        <u>   47</u>

The heat of solution of NaI is 47 kJ·mol⁻¹.

6 0
3 years ago
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