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mario62 [17]
2 years ago
12

Write and balance the equation for the dissolving of aluminium chloride into an aqueous solution with the dissociation of

Chemistry
1 answer:
umka2103 [35]2 years ago
6 0

The balanced equation for the dissolving of aluminum chloride into an aqueous solution with the dissociation of the ions is; AlCl3(s) → Al^3+ (aq) + 3 Cl^-(aq).

<h3>What is an equation?</h3>

An equation is a representation of the change that occurs inside a reaction vessel. Usually, we use this tool to show on paper, a process that we can not see with or eyes.

The equation that shows the balanced equation for the dissolving of aluminum chloride into an aqueous solution with the dissociation of the ions is; AlCl3(s) → Al^3+ (aq) + 3 Cl^-(aq).

Learn more about chemical equation: brainly.com/question/20492533

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At equilibrium, the concentrations of reactants and products can be predicted using the equilibrium constant, Kc, which is a mat
mr Goodwill [35]

Answer:

The equillibrium constant Kc = 11.2233

Explanation:

Step 1:

aA + bB ⇔ cC + dD

with a, b, c and d = coefficients

Kc = equillibrium constant =( [C]^c [D]^d ) / ( [A]^a [B]^b)

Concentration at time t

[A] = 0.300 M

[B] =1.10 M

[C] = 0.450 M

 

Change :

A: -x

B: -2x

C: -x

The following reaction occurs and equillibrium is established

A + 2B ⇔ C

[A] = 0.110M

[B] = ?

[C] = 0.640 M

For A we see that after change: 0.3 -x = 0.11

Then for B we have  1.1 - 2x = ? ⇒ 1.1 -2 *0.19 = 0.72

This gives us for the equillibrium constant Kc = [C] / [A][B] ²

Kc = 0.64 / (0.11) * (0.72)² = 11.2233

8 0
3 years ago
In a semi-crystalline polymer processed from solution, the presence of residual solvent will both decrease and broaden the melti
Rainbow [258]

Explanation:

The presence of residual solvent is a factor that affects the glass temperature of the polymer. This is because a residual solvent decreases the free volume in a polymer. All types of polymers have total occupied volume, which is composed of an occupied volume and a free volume. The free volume is the volume needed for the polymer chains to move around. Thus, if there is a big free volume in the polymer it will decrease the glass transition temperature and will both decrease and broaden the melting range of the crystals.

In a polymer with crystalline spherulites and the surrounding amorphous, will have a bigger surrounding amorphous with the presence of residual solvent. Which will decrease the melting range of the crystals. The structure found on the interior of the spherulites is pure crystalline polymer, so probably the residual solvent will not be inside them.

6 0
3 years ago
A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce
Leno4ka [110]

Answer:

The answers to the questions are;

a. The entropy of sublimation for carbon dioxide (the system) is  

134.07 J/Kmol.

b. The entropy of the universe for this reversible process is 376 J/K.

Explanation:

Entropy of sublimation is the entropy change experienced following the transformation of a mole of solid to vapor at  the temperature where the sublimation is taking place

a. We note that the mass of the solid CO₂ = 389 g

Molar mass of CO₂ = 44.01 g/mol

Number of moles of CO₂ in the sculpture = Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 Moles

Entropy of sublimation is given by

ΔS_{sublimation} = S_{vapor} - S_{solid} = \frac{\Delta H_{sublimation}}{T}

Where:

ΔH_{sublimation}  = 26.1 KJ/mol

T = Temperature = –78.5°C = ‪194.65‬ K

Therefore the amount of heat required to cause the 389 g of dry ice to sublime =    26.1 KJ/mol  × 8.84 Moles = 230.695 KJ

Therefore the entropy of sublimation = ΔS_{sublimation} = \frac{230.695 KJ}{194.65 K}

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol

b. The entropy of the universe is given by;

ΔS_{universe} = \Delta S_{system} + ΔS_{surrounding}  

If the heat absorbed by the system is the same as the heat given off by the surrounding, then we have;

ΔS_{universe} = \frac{Q}{ T_{system}}  -\frac{Q}{T_{surrounding}}  

                =1.185 KJ/K - -\frac{230.695 KJ}{285.15K} = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

7 0
3 years ago
Which type of substance have a definite shape and fixed volume?
IRINA_888 [86]
The answer is A. Solids only
8 0
3 years ago
Read 2 more answers
Plants remove which greenhouse gas from the atmosphere?
sineoko [7]
Hello there.

Question: <span>Plants remove which greenhouse gas from the atmosphere?

Answer: It is C. Carbon Dioxide. As you know, plants take in carbon dioxide and let out oxygen.

Hope This Helps You!
Good Luck Studying ^-^</span>
5 0
3 years ago
Read 2 more answers
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